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seraphim [82]
3 years ago
12

Using the order of operations solve the following: 60÷5(7-2)

Mathematics
1 answer:
Natasha2012 [34]3 years ago
3 0
60÷5=12 (7-2)=5 125=60×
You might be interested in
Check all the statements that are true:
Dahasolnce [82]

Answer:

The true statements are;

A, B, G, H, I, J

Step-by-step explanation:

To answer the question, we test each option as follows

A. If a and b both divide c, then ab divides c².

The above statement is true as c/a exists,

c/b exits therefore c²/ab = c/a×c/b

B. If p and q are distinct primes, then p2q2 has exactly 11 positive divisors.

The above statement is true as p² and q² each have 3 positive divisors, therefore, p²q² will also have pq and p²q² as possible divisors, therefore, true

C. If p and q are distinct primes, then p+q is prime as well.

The above statement is not correct as 5 + 7 = 12 an even number

D. If a divides b and c divides d, then a+c divides b+d.

The above statement is not correct as

8 is divisible by 2 and

9 is divisible by 3

but 17 is not divisible by 5

E. If p is prime, then so is p+2.

The above statement is not correct as 7 + 2 = 9 which is divisible by 3

G. If a and b both divide c, and a and b are relatively prime, then ab divides c.

The above statement is true as both a and b are factors of c

H. There are infinitely many prime numbers.

The above statement is true as there are infinitely many numbers

I. If p is prime, then p2 has exactly 3 positive divisors.

The above statement is true

1, p and p²

J. There are three consecutive odd numbers that are prime.

The above statement is true

3, 5, 7.

4 0
3 years ago
What is the GCF of 20, 36 and 48
nlexa [21]
20= 1,2,4,5,10,20
36=1,2,3,4,6,9,12,18,36
48=1,2,3,4,6,8,12,16,24,48
6 0
3 years ago
How can you express 5 1/3 + (-7 2/3) as the sum of its integer and fractional parts
Yuliya22 [10]

Answer:

-7/3

Step-by-step explanation:

-7 2/3=-23/3

5 1/3=16/3

-----------------

16/3+(-23/3)

16/3-23/3

-7/3

6 0
3 years ago
A sample of radium has a weight of 1.5 mg and a half-life of approximately 6 years.
pogonyaev

Answer:

0.75 mg

Step-by-step explanation:

From the question given above the following data were obtained:

Original amount (N₀) = 1.5 mg

Half-life (t₁/₂) = 6 years

Time (t) = 6 years

Amount remaining (N) =.?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Half-life (t₁/₂) = 6 years

Time (t) = 6 years

Number of half-lives (n) =?

n = t / t₁/₂

n = 6/6

n = 1

Finally, we shall determine the amount of the sample remaining after 6 years (i.e 1 half-life) as follow:

Original amount (N₀) = 1.5 mg

Half-life (t₁/₂) = 6 years

Number of half-lives (n) = 1

Amount remaining (N) =.?

N = 1/2ⁿ × N₀

N = 1/2¹ × 1.5

N = 1/2 × 1.5

N = 0.5 × 1.5

N = 0.75 mg

Thus, 0.75 mg of the sample is remaining.

5 0
2 years ago
A commercial aircraft gets the best fuel efficiency if it operates at a minimum altitude of 29,000 feet and a maximum altitude o
natita [175]

Answer:

x\geq 29,000  and  x\leq 41,000

Step-by-step explanation:

Let

x -----> the altitude of a commercial aircraft

we know that

The expression " A minimum altitude of 29,000 feet" is equal to

x\geq 29,000

All real numbers greater than or equal to 29,000 ft

The expression " A maximum altitude of 41,000 feet" is equal to

x\leq 41,000

All real numbers less than or equal to 41,000 ft

therefore

The compound inequality is equal to

x\geq 29,000  and  x\leq 41,000

All real numbers greater than or equal to 29,000 ft and less than or equal to 41,000 ft

The solution is the interval ------> [29,000,41,000]

5 0
3 years ago
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