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seraphim [82]
3 years ago
12

Using the order of operations solve the following: 60÷5(7-2)

Mathematics
1 answer:
Natasha2012 [34]3 years ago
3 0
60÷5=12 (7-2)=5 125=60×
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Please help with this will give you brainliest
Maslowich

The answer is 72  (--> second choice).

I can prove it without calculator so you believe me:

6\sqrt{8}\cdot3\sqrt{2}=6\cdot3\cdot\sqrt{8}\sqrt{2}=6\cdot3\cdo\sqrt{8\cdot2}=\\= 6\cdot3\cdot\sqrt{16}=6\cdot 3\cdot 4 = 72

7 0
3 years ago
Please help, test review. Need done today
ANTONII [103]
D=number of drinks
p=number of bags of popcorn

75=6d+8p
100.50=12d+10p

multiply first equation by -2 and add to first
-49.50=-6p
divide -6
8.25=p
sub

100.50=12d+10p
100.50=12d+82.50
minus 82.50
18=12d
divide 12
1.50=d

$1.50 per drink

YOU BETTER READ AND LEARN AND NOT JUST USE THIS TO PASS, LEARN

7 0
3 years ago
LCM OF 24,39,60 and 150 is<br>​
Salsk061 [2.6K]

Answer:

The LCM of 24,39,60, and 150 is 7,800.

Step-by-step explanation:

I use prime factorization and then I mulitply all of the double numbers.

8 0
3 years ago
#14 <br> quick answer pls :)
Andrej [43]

Answer:

35.56

Step-by-step explanation:

4 0
1 year ago
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }&#10;\\\\&#10;\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1&#10;\qquad &#10;\begin{cases}&#10;center\ ( h, k)\\&#10;vertices\ ( h,  k\pm a)\\&#10;c=\textit{distance from}\\&#10;\qquad \textit{center to foci}\\&#10;\qquad \sqrt{ a ^2 + b ^2}\\&#10;asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)&#10;\end{cases}\\\\&#10;-------------------------------

\bf \begin{cases}&#10;h=2\\&#10;k=-3\\&#10;a=6\\&#10;c=2\sqrt{10}&#10;\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2&#10;\\\\\\&#10;4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2&#10;\\\\\\&#10;\sqrt{4}=b\implies 2=b\\\\&#10;-------------------------------\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
2 years ago
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