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yulyashka [42]
4 years ago
3

Calculating Force What force would be required to accelerate a 1.100 kg car to 0.5 m/s??

Physics
2 answers:
viva [34]4 years ago
7 0

Answer:

0.55N

Explanation:

F(force)=m(mass)a (acceleration)

force equals mass times acceleration.

1.100 kilograms times 0.05 meters per second equals 0.55 Newtons, which is what you measure force in.

baherus [9]4 years ago
7 0

Answer:0.55N

Explanation:

initial velocity(v)=0m/s

mass(m)=1.100kg

Final velocity(v)=0.5m/s

Acceleration=(v-u)/t

Acceleration=(0.5-0)/1

Acceleration=0.5m/s^2

Force=mass x acceleration

Force=1.100 x 0.5

Force=0.55N

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PLEASE HELP!! Newtons first law states that if an objects velocity is changing a __________ must be acting on it. Question 1 opt
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Newtons first law states that if an objects velocity is changing a <u>force</u> must be acting on it.

Explanation:

Newton's first law of motion states that:

"An object at rest (or in uniform motion) will remain at rest (or will continue moving with the same velocity) unless acted upon an unbalanced force"

We can apply this law to a daily life example:

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  • Take a space probe moving in the interstellar space, very far from any planet or source of gravitational force. Since there are no forces acting on the proble, the probe will continue moving at the same velocity (same speed and same direction) forever, unless stopped by a new force acting on it.

This means that in order to put an object at rest in motion, or to stop an object already in motion, or to change its velocity, an unbalanced force needs to be applied: otherwise, the object will continue having the same velocity (which can be either zero or non-zero), so it will continue having  same speed and same direction.

Learn more about Newton laws of motion:

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5 0
3 years ago
A satellite in the shape of a solid sphere of mass 1,900 kg and radius 4.6 m is spinning about an axis through its center of mas
algol [13]

Answer:

6.3 rev/s

Explanation:

The new rotation rate of the satellite can be found by conservation of the angular momentum (L):

L_{i} = L_{f}

I_{i}*\omega_{i} = I_{f}*\omega_{f}

The initial moment of inertia of the satellite (a solid sphere) is given by:

I_{i} = \frac{2}{5}m_{s}r^{2}

Where m_{s}: is the satellite mass and r: is the satellite's radium

I_{i} = \frac{2}{5}m_{s}r^{2} = \frac{2}{5}1900 kg*(4.6 m)^{2} = 1.61 \cdot 10^{4} kg*m^{2}

Now, the final moment of inertia is given by the satellite and the antennas (rod):

I_{f} = I_{i} + 2*I_{a} = 1.61 \cdot 10^{4} kg*m^{2} + 2*\frac{1}{3}m_{a}l^{2}

Where m_{a}: is the antenna's mass and l: is the lenght of the antenna

I_{f} = 1.61 \cdot 10^{4} kg*m^{2} + 2*\frac{1}{3}150.0 kg*(6.6 m)^{2} = 2.05 \cdot 10^{4} kg*m^{2}

So, the new rotation rate of the satellite is:

I_{i}*\omega_{i} = I_{f}*\omega_{f}

\omega_{f} = \frac{I_{i}*\omega_{i}}{I_{f}} = \frac{1.61 \cdot 10^{4} kg*m^{2}*8.0 \frac{rev}{s}}{2.05 \cdot 10^{4} kg*m^{2}} = 6.3 rev/s  

Therefore, the new rotation rate of the satellite is 6.3 rev/s.

I hope it helps you!  

5 0
4 years ago
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