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oee [108]
3 years ago
5

A person is going to take a trip from town eight to town D to do this they travel 60 KM in .45 hour And then stop in town before

lunch it takes. 15 hour in the journey continues to town see over .5 hour and covers a distance of 30 KM they had to stop and pick up an item at the store that took .15 hour they restart their trip it took 1.5 hours to get to town which is 90 came away from town see what was a numerical value for the average speed of the trip
Physics
1 answer:
ANEK [815]3 years ago
4 0

Answer:

   v = 72 km / h

Explanation:

The definition of average speed is the distance traveled between the time interval

          v = Δx / Δt

let's find the distance traveled

       x = 60 + 30

       x = 90 km

time spent, all time must be included, travel time and when stopped

       t = 0.45 + 0.15 + 0.5+ 0.15

       t = 1.25 h

we substitute in the initial equation

      v = 90 / 1.25

       v = 72 km / h

in going from one city to the other

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3 years ago
You are working as an assistant to an air-traffic controller at the local airport, from which small airplanes take off and land.
Alika [10]

Answer:

d = 2021.6 km

Explanation:

We can solve this distance exercise with vectors, the easiest method s to find the components of the position of each plane and then use the Pythagorean theorem to find distance between them

Airplane 1

Height   y₁ = 800m

Angle θ = 25°

           cos 25 = x / r

           sin 25 = z / r

           x₁ = r cos 20

           z₁ = r sin 25

          x₁ = 18 103 cos 25 = 16,314 103 m = 16314 m

          z₁ = 18 103 sin 25 = 7,607 103 m= 7607 m

2 plane

Height   y₂ = 1100 m

Angle θ = 20°

          x₂ = 20 103 cos 25 = 18.126 103 m = 18126 m

          z₂ = 20 103 without 25 = 8.452 103 m = 8452 m

The distance between the planes using the Pythagorean Theorem is

         d² = (x₂-x₁)² + (y₂-y₁)² + (z₂-z₁)²2

Let's calculate

        d² = (18126-16314)²  + (1100-800)² + (8452-7607)²

        d² = 3,283 106 +9 104 + 7,140 105

        d² = (328.3 + 9 + 71.40) 10⁴

        d = √(408.7 10⁴)

        d = 20,216 10² m

        d = 2021.6 km

7 0
4 years ago
A 1500 kg car is parked at the top of a hill 5.2 m high. At the bottom of the hill, what is the kinetic energy, in Joules, of th
irga5000 [103]

Answer:

10.1

Explanation:

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3 years ago
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3 years ago
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When point charges q = +8.4 uC and q2 = +5.6 uC are brought near each other, each experiences a repulsive force of magnitude 0.6
Stella [2.4K]

Answer:

it is separated by 80 cm distance

Explanation:

As per Coulombs law we know that force between two point charges is given by

F = \frac{kq_1q_2}{r^2}

here we know that

q_1 = +8.4\mu C

q_2 = +5.6 \mu C

force between two charges is given as

F = 0.66 N

now we have

F = \frac{kq_1q_2}{r^2}

0.66 = \frac{(9\times 10^9)(8.4 \mu C)(5.6 \mu C)}{r^2}

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3 years ago
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