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HACTEHA [7]
3 years ago
6

Sort the following chemicals for their ability to act as an oxidizer. List from strongest to weakest; 1 being strongest, 6 being

weakest. (1-6)
Ag
Ni
K
Au
Cu
Ca
Chemistry
1 answer:
pashok25 [27]3 years ago
7 0
1.) K - potassium
2.) Ca - calcium
3.) Ni - nickle
4.) Cu - copper
5.) Ag - silver
6.) Au - gold

following the reactivity series from most to least reactive.
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The empirical formula of styrene is CH; its molar mass is 104.1 g/mol. What is the molecular formula of styrene
frez [133]
  • The atomic mass of carbon is 12.011 g/mol.
  • The atomic mass of hydrogen is 1.00794 g/mol.

This means the molar mass of CH is

12.011+1.00794=13.01894 \text{ g/mol}

Dividing the given molar mass by this,\frac{104.1}{13.01894} \approx 8

This means the molecular formula is \boxed{\text{C}_{8}\text{H}_{8}}

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<span>C + O2 → CO2 (8,376,726 tons) x (0.80) / (12.01078 g C/mol) x (1 mol CO2/ 1 mol C) x (44.00964 g CO2/mol) = 24,555,054 tons CO2</span>
6 0
4 years ago
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Calculate the number of grams of solute in 500.0 mL of 0.189 M KOH.
KIM [24]

Answer : The number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams

Solution : Given,

Volume of solution = 500 ml

Molarity of KOH solution = 0.189 M

Molar mass of KOH = 56 g/mole

Formula used :

Molarity=\frac{\text{Mass of KOH}\times 1000}{\text{Molar mass of KOH}\times \text{Volume of solution in ml}}

Now put all the given values in this formula, we get the mass of solute KOH.

0.189M=\frac{\text{Mass of KOH}\times 1000}{(56g/mole)\times (500ml)}

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Therefore, the number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams

7 0
3 years ago
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Ksenya-84 [330]

Answer:

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Explanation:

Hope this helps!

4 0
3 years ago
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oksian1 [2.3K]
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1092.2mmHg * 14.7psi / 760 mmHg = 21.13 psi

Answer: option D. 21.13 psi
7 0
4 years ago
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