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3 years ago

Helppppppp meeeeeeeeeeeee

Chemistry

2 answers:

Vilka [71]3 years ago

8 0

C yea I hope I’m right

Vadim26 [7]3 years ago

4 0

Answer:

Explanation:

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In this owl pellet dissection, from a pellet provided information on the that each owl ate. Some of the bones in the pellet were

sladkih [1.3K]

Answer:

In this owl pellet dissection, BONES from a pellet provided information on the PREY that each owl ate. Some of the bones in the pellet were common to all three owls and some of the bones were unique to particular prey. Identifying the unique prey allowed us to determine which ENVIRONMENT each owl was from.

Explanation:

1st -BONES

2nd - PREY

3rd - ENVIRONMENT

5 0

4 years ago

Does the suns light exhibit an emission spectrum?

algol13

Light is emitted in the visible spectrum to nearly all energies, so in the spectrum of the Sun you can see all colours. This is clearly not a continuous spectrum, but still represents visible radiation, divided into its component colours.

7 0

3 years ago

Find the equilibrium value of [CO] if Kc=14.5 : CO (g) + 2H2 (g) ↔ CH3OH (g) Equilibrium concentrations: [H2] = 0.322 M and [CH3

Annette [7]

Answer:

The equilibrium value of [CO] is 1.04 M

Explanation:

Chemical equilibrium is the state to which a spontaneously evolving chemical system, in which a reversible chemical reaction takes place. When this situation is reached, it is observed that the concentrations of substances, both reagents and reaction products, they remain constant over time. That is, the rate of reaction of reagents to products is the same as that of products to reagents.

Reagent concentrations and products in equilibrium are related by the equilibrium constant Kc. Being:

aA + bB ⇔ cC + dD

$Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }$

Then this constant Kces equals the multiplication of the concentrations of the products raised to their stoichiometric coefficients between the multiplication of the concentrations of the reactants also raised to their stoichiometric coefficients.

In this case:

$Kc=\frac{[CH_{3}OH ]}{[CO]*[H_{2} ]^{2} }$

You know:

Kc= 14.5
[H₂]= 0.322 M
[CH₃OH] =1.56 M

Replacing:

$14.5=\frac{1.56}{[CO]*0.322^{2} }$

Solving:

$[CO]=\frac{1.56}{14.5*0.322^{2} }$

[CO]= 1.04 M

The equilibrium value of [CO] is 1.04 M

8 0

3 years ago

Is it possible for an object to use or contain more than one energy form?

Feliz [49]

Answer:

Yes

Explanation:

There are 2 energy forms which one can transfer to and or from. An objects energy can be converted from one form to another.

7 0

3 years ago

A sample of marble has a volume of 6 cm and a density of 2.76 g/cm3. What is its mass?

Alexus [3.1K]

Answer:

16.56g

Explanation:

d=m/v

2.76=m/6

2.76*6=m

16.56=m

m=16.56g

3 0

3 years ago