Which set of compounds illustrates the law of multiple proportions? so2, so3 h2o, h2o2 n2o, no, no2 all of these?

1 answer:

7 0

<span>All of these. All the gases that are mentioned in each set identify with the law of multiple proportions since the all the compounds have oxygen ions in them. Law of multiple proportions is defined as formation of compound with oxide ions after the reaction of an element with oxygen.</span>

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What is the pH of a 2.0 x 10^-4 M solution of nitric acid (HNO3)

Semmy [17]

Hello!

datos:

Molarity = $2.0*10^{-4}\:M\:(mol/L)$

ps: The ionization constant of the nitric acid is strong (100% ionized in water) or completely dissociates in water, so the pH will be:

$pH = - log\:[H_3O^+]$

$pH = - log\:[2*10^{-4}]$

$pH = 4 - log\:2$

$pH = 4 - 0.30$

$\boxed{\boxed{pH = 3.70}}\end{array}}\qquad\checkmark$

Note:. The pH <7, then we have an acidic solution.

I Hope this helps, greetings ... DexteR!

3 0

3 years ago

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Consider the combustion of octane (C8H18)

sesenic [268]

The balanced equation for the above reaction is as follows;
2C₈H₁₈ + 25O₂ ---> 16CO₂ + 18H₂O
stoichiometry of octane to CO₂ is 2:16
number of C₈H₁₈ moles reacted - 191.6 g / 114 g/mol = 1.68 mol
when 2 mol of octane reacts it forms 16 mol of CO₂
therefore when 1.68 mol of octane reacts - it forms 16/2 x 1.68 = 13.45 mol of CO₂
number of CO₂ moles formed - 13.45 mol
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3 years ago

3.65 gram of hcl is dissolved in 180 gram of water. Find the total number of molecules of hydrogen

Morgarella [4.7K]

Answer:

$Molec_{\ H_{tot}}=1.206x10^{25}molec$

Explanation:

Hello.

In this case, taking into account that HCl has one molecule of hydrogen per mole of compound which weights 36.45 g/mol, we compute the number of molecules of hydrogen in hydrochloric acid by considering the given mass and the Avogadro's number:

$molec_{\ H}=3.65gHCl*\frac{1molHCl}{36.45gHCl} *\frac{1molH}{1molHCl}*\frac{6.022x10^{23}molec_\ H}{1molH} =6.03x10^{22}molec$

Now, from the 180 g of water, we see two hydrogen molecules per molecule of water, thus, by also using the Avogadro's number we compute the molecules of hydrogen in water:

$molec_{\ H}=180gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O}*\frac{6.022x10^{23}molec_\ H}{1molH} =1.20x10^{25}molec$