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scoundrel [369]
1 year ago
7

Graph the exponential model

Mathematics
1 answer:
Semmy [17]1 year ago
7 0

Answer: (1, 18)

Step-by-step explanation:

Test each x, y pair.

Getting to the last one, plug in 1 for the x value.

y = 3 * (6 ^ x)

y = 3 * (6 ^ 1)

y = 3 * 6

y = 18

This matches with (1, 18) so it must lie on the graph.

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A jewelry supply shop buys silver chains from a manufacturer for c dollars each, and then sells the chains at a 57% markup. Find
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A six-sided die is loaded in such a way that the probability of each face turning up is proportional to the number of dots on th
agasfer [191]

Answer:

P(2U5) = 7/21 = 1/3

the probability of getting either a 5 or a 2 in one throw is 1/3

Step-by-step explanation:

Given that; the probability of each face turning up is proportional to the number of dots on that face

P(1) = 1×P(1)

P(2) = 2×P(1)

P(3) = 3×P(1)

P(4) = 4×P(1)

P(5) = 5×P(1)

P(6) = 6×P(1)

P(T) = 21×P(1)

Where;

P(x) is the probability of getting number x on the dice.

P(T) is the total probability of obtaining any number

N(x) is the number of possible number x in terms of the distribution function.

P(x) = N(x)/N(T) ....1

And since P(T) is constant, and P(T) is proportional to N(T) then,

P(x) is directly proportional to N(x)

So, equation 1 becomes;

P(x) = N(x)/N(T) = P(x)/P(T) ....2

The probability of getting either a 5 or a 2 in one throw

P(2U5) = (P(2) + P(5))/P(T)

Substituting the values of each probability;

P(2U5) = (2P(1) + 5P(1))/21P(1)

P(2U5) = 7P(1)/21P(1)

P(1) cancel out, to give;

P(2U5) = 7/21 = 1/3

the probability of getting either a 5 or a 2 in one throw is 1/3

8 0
3 years ago
What binomial do you have to add to the polynomial:
marshall27 [118]

Answer:

a)  -2x^2+5xy

b)  -3y^2+5xy

Step-by-step explanation:

<u>Part (a)</u>

Given polynomial  :2x^2+3y^2-5xy+1

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable x is:

-2x^2+5xy

(2x^2+3y^2-5xy+1)+(-2x^2+5xy)

=2x^2+3y^2-5xy+1-2x^2+5xy

=2x^2-2x^2+3y^2-5xy+5xy+1

=3y^2+1

<u>Part (b)</u>

Given polynomial  :2x^2+3y^2-5xy+1

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable y is:

-3y^2+5xy

(2x^2+3y^2-5xy+1)+(-3y^2+5xy)

=2x^2+3y^2-5xy+1-3y^2+5xy

=2x^2+3y^2-3y^2-5xy+5xy+1

=2x^2+1

7 0
2 years ago
Pls help me with this, tyyy!
Olenka [21]

Answer:

Input : 12

Output : -48

Step-by-step explanation:

Hope it helped

6 0
2 years ago
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