Answer:
34%
Step-by-step explanation:
Given that the distribution of daily light bulb request replacement is approximately bell shaped with ;
Mean , μ = 45 ; standard deviation, σ = 3
Using the empirical formula where ;
68% of the distribution is within 1 standard deviation from the mean ;
95% of the distribution is within 2 standard deviation from the mean
Lightbulb replacement numbering between ;
42 and 45
Number of standard deviations from the mean /
Z = (x - μ) / σ
(x - μ) / σ < Z < (x - μ) / σ
(42 - 45) / 3 = -1
This lies between - 1 standard deviation a d the mean :
Hence, the approximate percentage is : 68% / 2 = 34%
9514 1404 393
Answer:
8 in by 16 in
Step-by-step explanation:
In your equation, we presume that x represents the width. Solving for x, we have ...
2x² = 128 . . . . . . given equation
x² = 64 . . . . . . . . divide by 2
x = √64 = 8 . . . . square root
The enlargement will be 8 inches by 16 inches.
I’m Not 100% Sure, But I Would Think 13.1% Is The Answer.
1.60 mi +1.75 mi = 3.35 mi = 3 7/20 mi
Answer irdk just need points lol.
