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Dvinal [7]
3 years ago
8

100 children attended a play on the trip 0.6 were girls. Which fraction represents the number of boys on the trip

Mathematics
1 answer:
Neporo4naja [7]3 years ago
7 0
Since 0.6 (or 60%) of the children were girls, 0.4 or 2/5 would be the answer for boys. 

Hope this helped!
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Bill wanted to try out different water craft he went 62 mikes downstream in a motor boat and 27 mikes down stream on a jest ski
valina [46]

Answer:

The speed on motorboat is 20 mph

Step-by-step explanation:

here, we want to find the speed on the motorboat

if he has a speed of x mph on the motor boat, his speed on the ski will be (x + 10) mph

The total hours is 4 hours

Mathematically; speed = distance/time

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Time on motor boat is 62/x

The addition of both is 4

Thus;

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89x + 620 = 4x^2 + 40x

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using the quadratic formula;

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where a = 4, b = -49 and c = -620

= 49 ± √(-49)^2-4(4)(-620)/8

So we have

49+ 111/8 or 49-111/8

Speed cannot be negative

(49 + 111)/8

= 20 mph

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Write expressions for the following scenarios.
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Answer:

flaimgo/albert

Step-by-step explanation:

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A triangle with sides 11m , 13m and 18m is a right triangle.<br> ​<br> A<br> True<br> B<br> False
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\bold{\huge{\pink{\underline{ Solution}}}}

\bold{\underline{ Given :-}}

  • <u>A </u><u>triangle </u><u>with </u><u>sides </u><u>11m</u><u>, </u><u> </u><u>13m </u><u>and </u><u>18m</u>

\bold{\underline{ To \: Find :-}}

  • <u>We</u><u> </u><u>have </u><u>to </u><u>check </u><u>it </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not</u><u>? </u>

\bold{\underline{ Let's \: Begin :-}}

\sf{\red{ In \:right \:angled\ : triangle, }}

According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.

<u>We </u><u>imply</u><u> </u><u>it </u><u>in </u><u>the </u><u>given </u><u>triangle </u><u>,</u>

\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}

\sf{(AB)² + (BC)² = (AC)²}

\sf{ (11)² + (13)² = (18)² }

\sf{ 121 + 169 ≠  324 }

\sf{ 290 ≠ 324  }

<u>From </u><u>Above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>

The sum of the squares of two small sides that is perpendicular height and base is not equal to the square of longest side that is Hypotenuse

\sf{\blue{ Hence,\: Your\: answer \:is \:false }}

5 0
2 years ago
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