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skelet666 [1.2K]
2 years ago
8

How would i draw the line y= -x

Mathematics
2 answers:
kykrilka [37]2 years ago
4 0

Answer:

Hope this helps :)

Step-by-step explanation:

Natali [406]2 years ago
4 0

Answer:

Step-by-step explanation:

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50 POINTS!
padilas [110]
To double the principle the formula is
2p=p e^rt
2=e^rt
2=e^0.12t
Solve for t
T=(log(2)÷log(e))÷0.12
T=5.78 years
5 0
3 years ago
How do you write 96% as a fraction in simplest form?
Troyanec [42]

Your answer would be 24/25

8 0
3 years ago
Read 2 more answers
30+30-2 hi brainly people and I
GrogVix [38]

Answer:

58

Step-by-step explanation:

Order of operations.

Additions and subtractions, in the order they appear, from left to right.

30 + 30 - 2 =

= 60 - 2

= 58

5 0
3 years ago
Read 2 more answers
All vectors are in Rn. Check the true statements below:
Oduvanchick [21]

Answer:

A), B) and D) are true

Step-by-step explanation:

A) We can prove it as follows:

Proy_{cv}y=\frac{(y\cdot cv)}{||cv||^2}cv=\frac{c(y\cdot v)}{c^2||v||^2}cv=\frac{(y\cdot v)}{||v||^2}v=Proy_{v}y

B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that ||Ax||=\sqrt{(A_1 x)^2+\cdots (A_n x)^2}. Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then ||Ax||=\sqrt{(x_1)^2+\cdots (x_n)^2}=||x||.

C) Consider S=\{(0,2),(2,0)\}\subseteq \mathbb{R}^2. This set is orthogonal because (0,2)\cdot(2,0)=0(2)+2(0)=0, but S is not orthonormal because the norm of (0,2) is 2≠1.

D) Let A be an orthogonal matrix in \mathbb{R}^n. Then the columns of A form an orthonormal set. We have that A^{-1}=A^t. To see this, note than the component b_{ij} of the product A^t A is the dot product of the i-th row of A^t and the jth row of A. But the i-th row of A^t is equal to the i-th column of A. If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then A^t A=I    

E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.

In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set \{u_1,u_2\cdots u_p\} and suppose that there are coefficients a_i such that a_1u_1+a_2u_2\cdots a_nu_n=0. For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then a_i||u_i||=0 then a_i=0.  

5 0
3 years ago
Three flavors of juice are offered at a school cafeteria The table shows the number of students who purchased each flavor during
Ilya [14]

Answer:  A. 0.2

Step-by-step explanation:

Probability for any event = \dfrac{\text{Favorable outcomes for event}}{\text{Total possible outcomes}}

Three flavors of juice are offered at a school cafeteria.

The given table:

Orange Grape   Cherry

51             30              69

Total juices = 51+30+69 =150

Now, the probability that a student who bought juice chosen at random purchased the grape flavor= \dfrac{\text{Number of grape juices}}{\text{Total juices}}

=\dfrac{30}{150}=0.2

Hence, the correct option is A.

6 0
3 years ago
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