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garik1379 [7]
3 years ago
10

Which triangle defined by the given points on the coordinate plane is similar to the triangle illustrated?

Mathematics
2 answers:
DiKsa [7]3 years ago
7 0

Answer:

its not C i got that wrong. still trying to figure out

Step-by-step explanation:

Kitty [74]3 years ago
6 0
C is your correct answer
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ycow [4]

Answer:

X+6

Step-by-step explanation:

Combined like terms.

7 0
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Can you please help me with this?​
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Answer:

first one i believe

Step-by-step explanation:

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2 years ago
Need help plzzzz will medal and fan
andriy [413]
The answer is f(x)=x²+2x when evaluated with -3 gives you the value of 3

Let's check all functions.
1. The function f(x)=x²<span>+2x when evaluated with 3 gives you the value of 3:
  Evaluated with x means that</span> x = 3.
   f(3) = 3² + 2 * 3 = 9 + 6 = 15 
   15 ≠ 3, so, this is not correct.

2. f(x)=x²<span>-3x when evaulated with -3 give you the value of 3
    Evaluated with -3 means that x = -3.
    (f-3) = (-3)</span>² - 3 * (-3) = 9 + 9 = 18 
    18 ≠ 3, so, this is not correct.

3. f(x)=x²<span>+2x when evaluated with -3 gives you the value of 3
</span>    Evaluated with -3 means that x = -3.
    f(-3) = (-3)² + 2 * (-3) = 9 - 6 = 3
    3 = 3, so this is correct.

4. f(x)=x²-3x when evaluated with -3 gives you the value of 3
    Evaluated with 3 means that x = 3.
    f(3) = (3)² - 3 * 3 = 9 - 9 = 0
    0 ≠ 3, so this is not correct.
6 0
3 years ago
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At most, how many unique roots will a third-degree polynomial function have?
beks73 [17]

The fundamental theorem of algebra states that a polynomial with degree n has at most n solutions. The "at most" depends on the fact that the solutions might not all be real number.

In fact, if you use complex number, then a polynomial with degree n has exactly n roots.

So, in particular, a third-degree polynomial can have at most 3 roots.

In fact, in general, if the polynomial p(x) has solutions x_1,\ x_2,\ldots x_n, then you can factor it as

p(x) = (x-x_1)(x-x_2)\ldots (x-x_n)

So, a third-degree polynomial can't have 4 (or more) solutions, because otherwise you could write it as

p(x)=(x-x_1)(x-x_2)(x-x_3)(x-x_4)

But this is a fourth-degree polynomial.

7 0
3 years ago
Please help me with this
oksano4ka [1.4K]

Answer:

m∠1=80°, m∠2=35°, m∠3=33°

Step-by-step explanation:

we know that

The sum of the interior angles of a triangle must be equal to 180 degrees

step 1

Find the measure of angle 1

In the triangle that contain the interior angle 1

∠1+69°+31°=180°

∠1+100°=180°

∠1=180°-100°=80°

step 2

Find the measure of angle 2

In the small triangle that contain the interior angle 2

∠2+45°+(180°-∠1)=180°

substitute the value of angle 1

∠2+45°+(180°-80°)=180°

∠2+45°+(100°)=180°

∠2+145°=180°

∠2=180°-145°=35°

step 3

Find the measure of angle 3

In the larger triangle that contain the interior angle 3

(∠3+31°)+69°+47°=180°

∠3+147°=180°

∠3=180°-147°=33°

3 0
2 years ago
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