Answer:
20 photos
Step-by-step explanation:
4 photos per page, 5 pages. 4 x 5 is 20.
1) Take the perimeter and divide it by 4.
2) Take the answer from step 1 and square it (multiply by itself)
The Bernoulli distribution is a distribution whose random variable can only take 0 or 1
- The value of E(x2) is p
- The value of V(x) is p(1 - p)
- The value of E(x79) is p
<h3>How to compute E(x2)</h3>
The distribution is given as:
p(0) = 1 - p
p(1) = p
The expected value of x2, E(x2) is calculated as:

So, we have:

Evaluate the exponents

Multiply

Add

Hence, the value of E(x2) is p
<h3>How to compute V(x)</h3>
This is calculated as:

Start by calculating E(x) using:

So, we have:


Recall that:

So, we have:

Factor out p

Hence, the value of V(x) is p(1 - p)
<h3>How to compute E(x79)</h3>
The expected value of x79, E(x79) is calculated as:

So, we have:

Evaluate the exponents

Multiply

Add

Hence, the value of E(x79) is p
Read more about probability distribution at:
brainly.com/question/15246027
Yes there is enough ribbon for a bow
Answer:

Step-by-step explanation:
<em>Time</em><em> </em>is the dependent variable, so you set your function equal to <em>s</em>. Then, the correlation of the graph has a
<em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em> </em>[<em>slope</em>] from the y-intercept of
so we choose this answer choice.
I am joyous to assist you anytime.