Calculate the primeter and area for each figure

Describe the sample space for each of these experiments (a) A coin is tossed and a single die is rolled. (b) A paper cup is toss

kondor19780726 [428]

Answer:

a) S={(head,1),(head,2),(head,3),(head,4),(head,5),(head,6),(tails,1),(tails,2),(tails,3),(tails,4),(tails,5),(tails,6)}

b) S={top,bottom,side}

c) S={(Ace of diamonds),(Two of diamonds),(Three of diamonds),(Four of diamonds),(Five of diamonds),(Six of diamonds),(Seven of diamonds), (Eight of diamonds),(Nine of diamonds),(Ten of diamonds), (Jack of diamonds), (Queen of diamonds), (King of diamonds), (Ace of hearts),(Two of hearts),(Three of hearts),(Four of hearts),(Five of hearts),(Six of hearts),(Seven of hearts), (Eight of hearts), (Nine of hearts),(Ten of hearts), (Jack of hearts), (Queen of hearts),(King of hearts),(Ace of clubs),(Two of clubs),(Three of clubs),(Four of clubs),(Five of clubs),(Six of clubs),(Seven of clubs), (Eight of clubs), (Nine of clubs),(Ten of clubs), (Jack of clubs),(Queen of clubs),(King of clubs),(Ace of spades),(Two of spades),(Three of spades),(Four of spades),(Five of spades),(Six of spades),(Seven of spades),(Eight of spades), (Nine of spades),(Ten of spades),(Jack of spades),(Queen of spades),(King of spades)}

Step-by-step explanation:

The sample space is all the possible outcomes from each experiment:

a) The sample has the pairs of the result of the coin (head or tails) and the dice (a number from 1 to 6):

S={(head,1),(head,2),(head,3),(head,4),(head,5),(head,6),(tails,1),(tails,2),(tails,3),(tails,4),(tails,5),(tails,6)}

b) A paper cup can land in three different ways, on its top, bottom or side:

S={top,bottom,side}

c) The sample space is all the cards in the deck:

S={(Ace of diamonds),(Two of diamonds),(Three of diamonds),(Four of diamonds),(Five of diamonds),(Six of diamonds),(Seven of diamonds), (Eight of diamonds),(Nine of diamonds),(Ten of diamonds), (Jack of diamonds), (Queen of diamonds), (King of diamonds), (Ace of hearts),(Two of hearts),(Three of hearts),(Four of hearts),(Five of hearts),(Six of hearts),(Seven of hearts), (Eight of hearts), (Nine of hearts),(Ten of hearts), (Jack of hearts), (Queen of hearts),(King of hearts),(Ace of clubs),(Two of clubs),(Three of clubs),(Four of clubs),(Five of clubs),(Six of clubs),(Seven of clubs), (Eight of clubs), (Nine of clubs),(Ten of clubs), (Jack of clubs),(Queen of clubs),(King of clubs),(Ace of spades),(Two of spades),(Three of spades),(Four of spades),(Five of spades),(Six of spades),(Seven of spades),(Eight of spades), (Nine of spades),(Ten of spades),(Jack of spades),(Queen of spades),(King of spades)}

3 0

3 years ago

X+24=35 how to solve this

timama [110]

Answer:

X = 11

Step-by-step explanation:

Simplifying

X + 24 = 35

Reorder the terms:

24 + X = 35

Solving

24 + X = 35

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-24' to each side of the equation.

24 + -24 + X = 35 + -24

Combine like terms: 24 + -24 = 0

0 + X = 35 + -24

X = 35 + -24

Combine like terms: 35 + -24 = 11

X = 11

Simplifying

X = 11

8 0

1 year ago

Read 2 more answers

At any point in time, there could be bicycles, tricycles, and

Aleksandr-060686 [28]

Answer:

There may be 1 or 3 tricycles in the parking lot.

Step-by-step explanation:

Since at any point in time, there could be bicycles, tricycles, and cars in the school parking lot, and today, there are 53 wheels in total, if there are 15 bicycles, tricycles, and cars in total, to determine how many tricycles could be in the parking lot, the following calculation must be performed:

13 x 4 + 1 x 3 + 1 x 2 = 57

11 x 4 + 1 x 3 + 3 x 2 = 53

10 x 4 + 3 x 3 + 2 x 2 = 53

8 x 4 + 5 x 3 + 2 x 2 = 51

10 x 2 + 1 x 3 + 4 x 4 = 39

9 x 3 + 1 x 2 + 5 x 4 = 49

Therefore, there may be 1 or 3 tricycles in the parking lot.

6 0

2 years ago

5. Two vertices of a rectangle are (8,-5) and (8,7). If the area of the rectangle is 72 square units, name the possible location

Phantasy [73]

Answer:

<u>Given vertices:</u>

(8, -5) and (8, 7)

These have same x-coordinate, so when connected form a vertical segment.

<u>The length of the segment is:</u>

7 - (-5) = 12 units

The area of the rectangle is 72 square units, so the horizontal segment has the length of:

72/12 = 6 units

<u>Possible location of the remaining vertices (to the left from the given):</u>

(8 - 6, -5) = (2, -5)

and

(8 - 6, 7) = (2, 7)

<u>Similarly to previous exercise:</u>

(5, -8) and (5, 4) given with the area of 48 square units

<u>The distance between the given vertices:</u>

4 - (-8) = 12 units

<u>The other side length is:</u>

48/12 = 4 units

<u>Possible location of the other vertices (to the right from the given):</u>

(5 + 4, -8) = (9, -8)

and

(5 + 4, 4) = (9, 4)

4 0

2 years ago

What is the simplest form of square root 1,764

oee [108]

$\bf \sqrt{1764}~~ \begin{cases} 1764=&2\cdot 2\cdot 3\cdot 3\cdot 7\cdot 7\\ &2^2\cdot 3^2\cdot 7^2\\ &(2\cdot 3\cdot 7)^2\\ &42^2 \end{cases}\implies \sqrt{42^2}\implies 42$

3 0

3 years ago