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Ganezh [65]
3 years ago
15

A car travels 0.75 miles every minute. Explain how you could use proportional reasoning to find how far the car travels in one h

our.
Mathematics
2 answers:
ra1l [238]3 years ago
4 0

Answer: Identify the unit rate as 0.75 miles per 1 minute. Since there are 60 minutes in an hour, multiply 0.75 time 60 to find how far the car travels in one hour.

dedylja [7]3 years ago
3 0
(0.75mi/1min)*(60min/1hour) = (45min/1hour)

By converting minutes into hours and multiplying 60 on the number of miles it travels for 1 minute, you get the number of miles the car has traveled in 60 minutes.
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What is 136°=92°+6r+2°​
Lina20 [59]

What is being solved for is r.

136 = 92 + 6r + 2

136 - 92 - 2 = 6r

42 = 6r

r = 6

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Find the quotient.<br> 0 divided by(-16
Blababa [14]

Answer:

0 ig

Step-by-step explanation:

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Solve the equation.
eimsori [14]

Answer:C

Step-by-step explanation:

6(x+7)=5(x-7)+x

⇔6x+42=5x-35+x

⇔6x-5x-x=-35-42

⇔0x=-77  

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3 years ago
An engineer's compensation package includes the total cost of a $175-per-month health insurance plan, the total cost of a $55-pe
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55000+175(12)+55(12)
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The answer is A.
3 0
4 years ago
(Uniform) Suppose X follows a continuous uniform distribution from 4 to 11. (a) Write down the PDF of X. (b) Find P(X ≤ 7). Roun
love history [14]

Answer:

a) f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11

b) P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286

c) P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857

d) P(X >5 | X \leq 7)

And we can find this probability with this formula from the Bayes theorem:

P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5

Step-by-step explanation:

For this case we assume that the random variable X follows this distribution:

X \sim Unif (a=4, b =11)

Part a

The probability density function is given by the following expression:

f(x) = \frac{1}{b-a} , a \leq x \leq b

f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11

Part b

We want this probability:

P(X \leq 7)

And we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a}= \frac{x-4}{11-4}

And replacing we got:

P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286

Part c

We want this probability:

P(5 < X \leq 7)

And we can use the CDF again and we have:

P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857

Part d

We want this conditional probabilty:

P(X >5 | X \leq 7)

And we can find this probability with this formula from the Bayes theorem:

P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5

7 0
3 years ago
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