Procedure:
1) Integrate the function, from t =0 to t = 60 minutues to obtain the number of liters pumped out in the entire interval, and
2) Substract the result from the initial content of the tank (1000 liters).
Hands on:
Integral of (6 - 6e^-0.13t) dt ]from t =0 to t = 60 min =
= 6t + 6 e^-0.13t / 0.13 = 6t + 46.1538 e^-0.13t ] from t =0 to t = 60 min =
6*60 + 46.1538 e^(-0.13*60) - 0 - 46.1538 = 360 + 0.01891 - 46.1538 = 313.865 liters
2) 1000 liters - 313.865 liters = 613.135 liters
Answer: 613.135 liters
Answer:
The value of <em>c</em> is 
.
Step-by-step explanation:
The perfect square of the difference between two numbers is:
The expression provided is:
The expression is a perfect square of the difference between two numbers.
One of the number is <em>x</em> and the other is √<em>c</em>.
Use the above relation to compute the value of <em>c</em> as follows:
![x^{2}-15x+c=(x-\sqrt{c})^{2}\\\\x^{2}-15x+c=x^{2}-2\cdot x\cdot\sqrt{c}+c\\\\15x=2\cdot x\cdot\sqrt{c}\\\\15=2\cdot\sqrt{c}\\\\\sqrt{c}=\frac{15}{2}\\\\c=[\frac{15}{2}]^{2}\\\\c=\frac{225}{4}](https://tex.z-dn.net/?f=x%5E%7B2%7D-15x%2Bc%3D%28x-%5Csqrt%7Bc%7D%29%5E%7B2%7D%5C%5C%5C%5Cx%5E%7B2%7D-15x%2Bc%3Dx%5E%7B2%7D-2%5Ccdot%20x%5Ccdot%5Csqrt%7Bc%7D%2Bc%5C%5C%5C%5C15x%3D2%5Ccdot%20x%5Ccdot%5Csqrt%7Bc%7D%5C%5C%5C%5C15%3D2%5Ccdot%5Csqrt%7Bc%7D%5C%5C%5C%5C%5Csqrt%7Bc%7D%3D%5Cfrac%7B15%7D%7B2%7D%5C%5C%5C%5Cc%3D%5B%5Cfrac%7B15%7D%7B2%7D%5D%5E%7B2%7D%5C%5C%5C%5Cc%3D%5Cfrac%7B225%7D%7B4%7D)
Thus, the value of <em>c</em> is .
Answer:
4/4
Step-by-step explanation:
2/3 * what = 8/12
Multiply the top and bottom by 4/4
2/3 *4/4 = 8/12
Answer:
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