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34kurt
3 years ago
9

At gary’s grocery, 3 apples cost $2.85. at sally’s supermarket, 5 apples cost $4.85. which store offers a cheaper price per appl

e? how do you know?
Mathematics
1 answer:
Fiesta28 [93]3 years ago
3 0
Gary's grocery store sells cheaper apples

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A negative correlation between two variables x and y usually yields a negative p-value for r.
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A. True if im wrong sorry hope this helped tho :p
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What is the slope of the line represented by the equation y=-1/2x+1/4
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The slope will be -1/2. If you put it into slope intercept form of y=mx+b, mx will always be the slope. 
7 0
3 years ago
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A case of tomato cans weighs 563 dekagrams. A case of soup cans weighs 458 dekagrams. How much do the two cases weigh together i
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Answer:

  102,100 decigrams

Step-by-step explanation:

  (564 dag + 458 dag) = 1021 dag

  1021 dag × 100 dg/dag = 102100 dg

The two cases together weigh 102,100 decigrams.

_____

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The quotient of n and 12 subtracted from 100?
Korvikt [17]

Answer:

100 - 12/n

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12/n

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100 - 12/n

If you're looking to evaluate it then it would be

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5 0
2 years ago
Which is the equation of a hyperbola centered at the origin with x-intercept +\- 3 and asymptote y=2x
Radda [10]

Answer:

{\dfrac{x^{2}}{9} - \dfrac{y^{2}}{36} = 1}

Step-by-step explanation:

The hyperbola has x-intercepts, so it has a horizontal transverse axis.

The standard form of the equation of a hyperbola with a horizontal transverse axis is  \dfrac{(x - h)^{2}}{a^{2}} - \dfrac{(y - k)^{2}}{b^{2}} = 1

The center is at (h,k).

The distance between the vertices is 2a.

The equations of the asymptotes arey = k \pm \dfrac{b}{a}(x - h)

1. Calculate h and k. The hyperbola is symmetric about the origin, so  

h = 0 and k = 0

2. For 'a': 2a = x₂ - x₁ = 3 - (-3) = 3 + 3 = 6

a = 6/2 = 3  

3. For 'b': The equation for the asymptote with the positive slope is  

y = k + \dfrac{b}{a}(x - h) = \dfrac{b}{a}x

Thus,  asymptote has the slope of

\begin{array}{rcl}m& =& \dfrac{b}{a}\\\\2& =& \dfrac{b}{3}\\\\b& =& \mathbf{6}\end{array}

4.  The equation of the hyperbola is

\large \boxed{\mathbf{\dfrac{x^{2}}{9} - \dfrac{y^{2}}{36} = 1}}

The attachment below represents your hyperbola with x-intercepts at ±3 and asymptotes with slope ±2.

7 0
2 years ago
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