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alex41 [277]
3 years ago
6

What are the fourth roots of 256

Mathematics
1 answer:
qwelly [4]3 years ago
7 0
The fourth root of 256 is 4:
{4}^{1}  = 4 \\  {4}^{2}  =4 \times 4 =  16 \\  {4}^{3}  = 16 \times 4 = 64 \\  {4}^{4}  =64 \times 4 =  256
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ollegr [7]
The Pythagorean Theorem states that a² + b² = c², c being the hypotenuse.


Substitute known values into the equation.

7² + 2² = c²
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4 years ago
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Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Divide 630 by 5 using partial quotients
ZanzabumX [31]
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5 0
4 years ago
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ollegr [7]

Answer:

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Step-by-step explanation:

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(4a + 7b  -12c) - (8a -9b +12d)

Now we have distribute the negative sign inside the second expression (8a -9b +12b). If we do, the sign changes.

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Now we can combine the like terms

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8 0
3 years ago
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