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Stels [109]
3 years ago
11

Which terms could be used as the last term of the expression below to create a polynomial written in standard form? Check all th

at apply. –5x2y4 + 9x3y3 + ___
x5
y5
–4x4y5
6x4y
–xy5
–x4/9
Mathematics
2 answers:
kogti [31]3 years ago
7 0
A polynomial is said to be in standard form if it is written in the order of degree from highest to lowest from left to right.

The degree of a term of a polynomial is the exponent of the variable or the sum of the exponents of the variables of that term of the polynomial.

Thus, given the expression
-5x^2y^4 + 9x^3y^3+\_\_\_

-5x^2y^4 has a degree of 6, and
9x^3y^3 has a degree of 6.

Thus, the exponent of the variable or the sum of the exponents of the variables of the next term of the polynomial must be less than or equal to 6 for the polynomal to be said to be in standars form.

Therefore, the <span>terms that could be used as the last term of the given expression to create a polynomial written in standard form are
x^5, \\  \\ &#10;y^5, \\  \\ &#10;6x^4y, \ and \\  \\ &#10;-xy^5</span>
charle [14.2K]3 years ago
4 0

The correct answers are 1,4,6.

A) x^5

D) 6x^4y

F) - x^4/9

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Parallelogram ABCD is dilated to form parallelogram EFGH. Side BC is proportional to side CD. Which corresponding side is propor
notsponge [240]

Answer:

It is given that , Parallelogram ABCD is dilated to form parallelogram EFGH.

When Dilation of a geometrical shape takes place, the two→→image and Pre image will be Similar.

Parallelogram ABCD ~ Parallelogram EFGH

Since Similar shapes have , Proportional side Lengths as well as length of their Diagonal will be proportional.

\frac{AB}{EF}=\frac{BC}{FG}=\frac{CD}{GH}=\frac{AD}{EH}=\frac{AC}{EG}=\frac{BD}{EG}

So, Segment FG will be proportional to Segment BC.

6 0
3 years ago
Read 2 more answers
the hu family goes out for lunch, and the price of the meal is $43. The sales tax on the meal is 6%, and the family also leaves
Anna007 [38]

Answer:

Step-by-step explanation:

43.00x.06=2.58

43.00x.15=6.45

43.00+2.58+6.45=54.03

6 0
3 years ago
A fair die is cast, a fair coin is tossed, and a card is drawn from a standard deck of 52 playing cards. Assuming these events a
dem82 [27]

Answer:

The probability is 0.0192 to four decimal places.

Step-by-step explanation:

In this question, we are asked to calculate the probabilities that three events will occur at the same time.

Firstly, we identify the individual probabilities.

The probability of 6 showing In a throw of die is 1/6

The probability of a coin showing head in a flip of coin is 1/2

The probability of a face card being drawn in a deck of cards is 12/52( There are 12 face cards in a deck of cards)

Mathematically to get the probability of all these events happening, we simply multiply all together.

This will be ;

1/6 * 1/2 * 12/52 = 1/52 = 0.0192 ( to 4 decimal place)

7 0
3 years ago
Read 2 more answers
I need help please!!!!!!!
KATRIN_1 [288]

Answer:

C

Step-by-step explanation:

I don't know for sure, but I am pretty sure this is it.

4 0
2 years ago
Read 2 more answers
Compound interest In Exercise,$3000 is invested in an account at interest rate r,compounded continuously.Find the time required
xenn [34]

Answer:

(a) 8.15

(b) 12.92

Step-by-step explanation:

Given: P = $3000, r = 0.085

                A = Pe^{rt}

Where

A is the Amount

P is the Principal

r is the rate

t is the time

(a) For the amount to double, A = 2 × P

               A = 2 × $3000

               A = $6000

               6000 = 3000e^{0.085t}

               \frac{6000}{3000} = e^{0.085t}

               2 = e^{0.085t}

Take log_{e} of both sides

               log_{e}2 = log_{e}e^{0.085t}

But log_{e}e = 1

            ∴ ln2 = 0.085t

               t = \frac{ln2}{0.085}

               t = \frac{0.693}{0.085}

               t = 8.15

(b) For the amount to double, A = 3 × P

               A = 3 × $3000

               A = $9000

               9000 = 3000e^{0.085t}

               \frac{9000}{3000} = e^{0.085t}

               3 = e^{0.085t}

Take log_{e} of both sides

               log_{e}3 = log_{e}e^{0.085t}

But log_{e}e = 1

            ∴ ln3 = 0.085t

               t = \frac{ln3}{0.085}

               t = \frac{1.0986}{0.085}

               t = 12.92

5 0
3 years ago
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