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2 years ago

Finish 7-8 all of it

Mathematics

1 answer:

Alik [6]2 years ago

7 0

7. you'd multiply 5 times each number in 198. so 5 times 8 gets you 40. carry the 4 to the and drop the 0. 5 times 9 gets you 45 + 4 gets you 49. carry the 4 to the 1 and drop the 9. do 5 times 1, gets you 5 + 4 and gets you 9. so your answer is 990

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PLZZZ HELP I'LL GIVR U A MEDAL N FAN U

disa [49]

The first option is correct I did this before hope this helps

6 0

3 years ago

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A road has a 10% grade, meaning increasing 1 unit of rise to every 10 units of run.

fenix001 [56]

The grade is the ratio of rise to run, i.e. the slope aka the tangent.

$\tan \theta = \dfrac{1}{10}$

$\theta = \arctan 0.1 \approx 5.711^\circ$

Answer: (a) 6 degrees

For part b, the road is the hypotenuse c of a right triangle whose tangent of the small angle is 1/10. The height h or rise is the side opposite the small angle.

$\sin\theta = \dfrac h c$

$h = c \sin \theta$

We could just take the sine of the angle we got but let's get it from the tangent exactly.

$\cos^2 \theta + \sin ^2 \theta = 1$

Dividing by squared cosine

$1 + \tan ^2 \theta = 1/\cos^2 \theta = 1/(1- \sin^2 \theta)$

$(1- \sin^2 \theta) = 1/(1 + \tan^2 \theta)$

$\sin^2 \theta = 1 - 1/(1 + \tan^2 \theta)$

$\sin^2 \theta = 1 - 1/(1 + (1/10)^2) = 1-1/(101/100) = 1/101$

$h = c \sin \theta = 2 \sqrt{1/101} \approx 0.199$

Answer: (b) Rise of 0.199 km

6 0

3 years ago

Use the unit price to find the total price.8 gallons at $1.94 per gallon

Alika [10]

1.94 / 8 = 0.2425 rounds to 0.24....so unit price is 24 cents per gallon

5 0

3 years ago

To find the extreme values of a function f(x,y) on a curve xequalsx(t), yequalsy(t), treat f as a function of the single vari

pychu [463]

Answer:

Absolute maximum is 2

Absolute minimum at -2

Step-by-step explanation:

The given parametric functions are:

$x=2\cos t,y=2\sin t$

By the chain rule:

$f'(t)=\frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$\frac{df}{dt} =\frac{2 \cos t}{-2\sin t} =-\cot(t)$

At fixed points, $f'(t)=0$

$\implies -\cot (t)=0$

This gives $t=\frac{\pi}{2} ,\frac{3\pi}{2}$ on $0\le t\le 2\pi$

This implies that the extreme points are $(2\cos \frac{\pi}{2}, 2\sin \frac{\pi}{2})=(0,2)$ and $(2\cos \frac{3\pi}{2}, 2\sin \frac{3\pi}{2})=(0,-2)$

By eliminating the parameter, we have $x^2+y^2=4$

This is a circle with radius 2, centered at the origin.

Hence (0,2) is an absolute maximum ,at $t=\frac{\pi}{2}$ and (0,-2) is an absolute minimum at $t=\frac{3\pi}{2}$

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2 years ago

Team A and Team B play in a competition.

Anuta_ua [19.1K]

Team A: 15 points
Team B: 3 points

Team A has twelve more points than Team B:
A = B + 12
Team A has five times as many points as Team B:
A = B × 5
A = 5B

substitute "A" with "B + 12" to solve for B:
A = 5B
(B + 12) = 5B
B + 12 = 5B
12 = 5B - B
12 = 4B
3 = B
Team B has 3 points
now substitute "B" with 3 to solve for A:
A = 5B
A = 5(3)
A = 15
Team A has 15 points

Check your answer by inputting both values into either equation:
A = 5B
(15) = 5(3)
15 = 15 ✔

A = B + 12
(15) = (3) + 12
15 = 15 ✔

8 0

2 years ago

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