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sukhopar [10]
3 years ago
10

What problem has the answer of square root 6/2?

Mathematics
1 answer:
Crazy boy [7]3 years ago
6 0
3........................................
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Wyd for 50 points answer fast
Vika [28.1K]

Answer: Chillin hbu?

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csec%5Cleft%28x%5Cright%29%7D%7B%5Ccos%5Cleft%28x%5Cright%29%7D-%5Cfrac%7B%5Csin%5
DanielleElmas [232]

Answer:

1

Step-by-step explanation:

First, convert all the secants and cosecants to cosine and sine, respectively. Recall that csc(x)=1/sin(x) and sec(x)=1/cos(x).

Thus:

\frac{sec(x)}{cos(x)} -\frac{sin(x)}{csc(x)cos^2(x)}

=\frac{\frac{1}{cos(x)} }{cos(x)} -\frac{sin(x)}{\frac{1}{sin(x)}cos^2(x) }

Let's do the first part first: (Recall how to divide fractions)

\frac{\frac{1}{cos(x)} }{cos(x)}=\frac{1}{cos(x)} \cdot \frac{1}{cos(x)}=\frac{1}{cos^2(x)}

For the second term:

\frac{sin(x)}{\frac{cos^2(x)}{sin(x)} } =\frac{sin(x)}{1} \cdot\frac{sin(x)}{cos^2(x)}=\frac{sin^2(x)}{cos^2(x)}

So, all together: (same denominator; combine terms)

\frac{1}{cos^2(x)}-\frac{sin^2(x)}{cos^2(x)}=\frac{1-sin^2(x)}{cos^2(x)}

Note the numerator; it can be derived from the Pythagorean Identity:

sin^2(x)+cos^2(x)=1; cos^2(x)=1-sin^2(x)

Thus, we can substitute the numerator:

\frac{1-sin^2(x)}{cos^2(x)}=\frac{cos^2(x)}{cos^2(x)}=1

Everything simplifies to 1.

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3 years ago
Marita orders 12 yards of material to make banners if she needs one foot of fabric for each Banner how many banners can she make
AleksandrR [38]
36 banners 12 yards=36Ft
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Which value of HNK are used to write the function f(x) = x2 + 12x + 6 in vertex form?
anygoal [31]

Answer:

( − 6 , − 30 )

Step-by-step explanation:

Rewrite in vertex form and use this form to find the vertex  ( h , k ) .

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What's X?<br> Please help me and explain
ANTONII [103]

Answer:

60 degree

Step-by-step explanation:

E,A,D is a straight line .

Straight line=180 degree

100+20=120 -180=60

therefore X=60

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