The info an atomic mass of an element provides is the nyumber of protons and neutrons in an atom
Answer:
<em>To reverse the direction of an electric current, we simply reverse the voltage either automatically with the help of some switching circuitry or manually by changing the voltage source terminals connection. </em>
Explanation:
For electric current to flow, there must be a potential difference, usually referred to as the voltage. The electric current flow is analogous to the flow of water under the action of a pump, through a series of pipe connections. The voltage is similar to the driving action of the pump, and current flows the same way water flows. The resistance due to drag on the pipe wall is equivalent to electric resistance. For current to flow in the reverse direction, the voltage or rather, the potential difference is changed, causing the current to flow in the opposite direction. This can be done by switching the terminals of the voltage source, or by automatic means. The automatic switching can be done with a transistor based circuitry.
Answer:
Explanation:
Given data :
Length of rubber tube = 13.6m
Mass of rubber tube = 0.750 kg
mass of object = 740 kg
gravitational acceleration = g = 9.8 m/s²
Solution:
First we will find mass per unit length of the rubber tube μ.
μ = 13.6/0.750
= 18.133 kg/m
tension in tube T = mg = 740×9.8
= 7252 N
now we have the values of T and μ we can find the speed v.
v = √T/μ
v = 19.998 m/s
= 13.6/19.998
t = 0.68 s
Answer: Kinect Energy
Explanation: As an object falls its potential energy decreases, while its kinetic energy increases. The decrease in potential energy is exactly equal to the increase in kinetic energy. ... In doing so, you have increased the potential energy of the book (by increasing its potential to fall down to the floor).
Answer:
It acts perpendicular to the velocity and is directed toward the center of the circle.
Explanation:
For a force to make an object move in a circular motion, the force must act perpendicular to the velocity and directed toward the center of the circle of motion as shown in the attached image.