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svp [43]
4 years ago
6

Which part of an atom is actively exchanged or shared in a chemical bond?

Physics
2 answers:
Kobotan [32]4 years ago
7 0

Answer:

The answer is electron!

Explanation:

Neporo4naja [7]4 years ago
4 0
The electron is actively exchanged in a chemical bond
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360 degrees. I'm pretty sure
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A G note has a frequency of 783.99 Hz. Calculate its wavelength in meters.
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A rock of mass m is thrown horizontally off a building from a height h. the speed of the rock as it leaves the thrower's hand at
Stells [14]
The correct answer is <span>3) K_f =  \frac{1}{2}mv_0^2 + mgh.
</span>
In fact, the total energy of the rock when it <span>leaves the thrower's hand is the sum of the gravitational potential energy U and of the initial kinetic energy K:
</span>E=U_i+K_i=mgh +  \frac{1}{2}mv_0^2
<span>As the rock falls down, its height h from the ground decreases, eventually reaching zero just before hitting the ground. This means that U, the potential energy just before hitting the ground, is zero, and the total final energy is just kinetic energy: 
</span>E=K_f<span>
But for the law of conservation of energy, the total final energy must be equal to the tinitial energy, so E is always the same. Therefore, the final kinetic energy must be
</span>K_f = mgh +  \frac{1}{2}mv_0^2<span>
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7 0
3 years ago
How does a distance-time graph show you which direction the runner is moving? Use your own words and science vocabulary.
Dmitry [639]

In a distance time graph, when the x and y values are positive (in first quadrant), the runner is moving forward.

While, if the distance value ( in the y axis) is negative, the runner is moving backwards ( towards the start) .

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8 0
3 years ago
4. Paper is solid in packets labelled 80 g/m2. This means that a sheet of paper of area
ira [324]

Answer:

Option C. 0.73 g/cm³

Explanation:

From the question given above, the following data were obtained:

Mass = 80 g

Area (A) = 10000 cm²

Thickness = 0.11 mm

Density =?

Next, we shall convert 0.11 mm to cm. This can be obtained as follow:

10 mm = 1 cm

Therefore,

0.11 mm = 0.11 mm × 1 cm / 10 mm

0.11 mm = 0.011 cm

Thus, 0.11 mm is equivalent to 0.011 cm.

Next, we shall determine the volume of the paper. This can be obtained as follow:

Area (A) = 10000 cm²

Thickness = 0.011 cm

Volume =?

Volume = Area × Thickness

Volume = 10000 × 0.011

Volume = 110 cm³

Finally, we shall determine the density of the paper. This can be obtained as follow:

Mass = 80 g

Volume = 110 cm³

Density =?

Density = mass / volume

Density = 80 / 110

Density = 0.73 g/cm³

Therefore the density of the paper is 0.73 g/cm³

3 0
3 years ago
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