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Nimfa-mama [501]
4 years ago
10

Master of physics needed

Physics
1 answer:
Delicious77 [7]4 years ago
8 0
Hey JayDilla, I get 1/3.  Here's how:
Kinetic energy due to linear motion is:
E_{linear}= \frac{1}{2}mv^2
where
v=r \omega
giving
E_{linear}= \frac{1}{2}mr^2 \omega ^2

The rotational part requires the moment of inertia of a solid cylinder
I_{cyl} =  \frac{1}{2}mr^2
Then the rotational kinetic energy is
E_{rot}= \frac{1}{2}I \omega ^2= \frac{1}{4}mr^2 \omega ^2
Adding the two types of energy and factoring out common terms gives
\frac{1}{2}mr^2 \omega ^2(1+ \frac{1}{2})
Here the "1" in the parenthesis is due to linear motion and the "1/2" is due to the rotational part.  Since this gives a total of 3/2 altogether, and the rotational part is due to a third of this (1/2), I say it's 1/3.

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Answer:

The minimum uncertainty in its position is 1.1587 nm

Explanation:

Given;

average speed of electron, v = 5.00 × 10⁶ m/s

percentage of speed uncertainty = 1%

Δv = 0.01( 5.00 × 10⁶ m/s) = 5.00 × 10⁴ m/s

Applying Heisenberg's uncertainty principle, to determine the uncertainty in its position.

ΔxΔP ≥ h/4π

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Δx = h/4πmΔv

where;

Δx is uncertainty in its position

h is Planck's constant

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Δx ≥ \frac{6.626 *10^{-34}}{4\pi *9.1*10^{-31}*5*10^4} = 1.1587*10^{-9} \ m

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Therefore, the minimum uncertainty in its position is 1.1587 nm

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3 years ago
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Answer:

The mass has likely lost some of its mechanical energy to resistance on its path.

Explanation:

The mechanical energy of an object is the sum of its kinetic and potential energies (KE and PE.) Ideally, the mechanical energy of a simply pendulum should be "conserved." In other words, the sum of the kinetic and potential energy of the simply pendulum should stays the same as it travels along its path.

Indeed, as the pendulum travels, some of its PE will convert to KE and back. However, the sum of these two energies is supposed to stay the same.

  • When the pendulum moves from the highest point to the bottom of the path, some of its PE converts to KE. (The pendulum speeds up in this process.)
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However, in practice, the mechanical energy of pendulums isn't always conserved. For example, various kinds of resistances (such as air resistance) act on the pendulum as it moves. That would slow down the pendulum. Some of the pendulum's energies would be converted to heat and is lost to the surroundings.

In effect, the mechanical energy of the pendulum would become smaller and smaller over time. When the pendulum travels back towards the girl, its potential energy would be smaller than the initial value when at the girl's chin.

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Answer:

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s= NOT NEEDED

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Gas produced - Whenever a gaseous product forms in a liquid solution, bubbles can be seen. A colorless gas produced in a reaction of solids is much harder to detect.
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