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RideAnS [48]
3 years ago
5

NUMBER 1 PLEASE ASAP

Mathematics
2 answers:
blsea [12.9K]3 years ago
6 0

Answer:

MAYBE: 14?

Step-by-step explanation:

i just read it in the pic above and worked it out.

lara [203]3 years ago
3 0

Answer:

43 / 3 = 14

Step-by-step explanation:

correct me if im wrong

Ill redo it

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We have seen that isosceles triangles have two sides of equal length. The angles opposite these sides have the same measure. Use
Naddik [55]

Question has missing figure, the figure is in the attachment.

Answer:

The measure of ∠1 is 65°.

The measure of ∠2 is 65°.

The measure of ∠3 is 50°.

The measure of ∠4 is 115°.

The measure of ∠5 is 65°.

Step-by-step explanation:

Given,

We have an isosceles triangle which we can named it as ΔABC.

In which Length of AB is equal to length of BC.

And also m∠B is equal to m∠C.

ext.m∠C= 115°(Here ext. stands for exterior)

We have to find the measure of angles angles 1 through 5.

Solution,

For ∠1.

∠1 and ext.∠C makes straight angle, and we know that the measure of straight angle is 180°.

So, we can frame this in equation form as;

\angle1+ext.\angle C=180\°

On putting the values, we get;

\angle 1+115\°=180\°\\\\\angle1=180\[tex]\therefore m\angle2=65\°-115\°=65\°[/tex]

Thus the measure of ∠1 is 65°.

For ∠2.

Since the given triangle is an isosceles triangle.

So, m\angle1=m\angle2

Thus the measure of ∠2 is 65°.

For ∠3.

Here ∠1, ∠2 and ∠3 are the three angles of the triangle.

So we use the angle sum property of triangle, which states that;

"The sum of all the angles of a triangle is equal to 180°".

\therefore \angle1+\angle2+\angle3=180\°

Now we put the values and get;

65\°+65\°+\angle3=180\°\\\\130\°+\angle3=180\°\\\\\angle3=180\°-130\°=50\°

Thus the measure of ∠3 is 50°.

For ∠4.

∠4 and ∠2 makes straight angle, and we know that the measure of straight angle is 180°.

So, we can frame this in equation form as;

\angle2 +\angle 4 =180\°

Substituting the values of of angle 2 to find angle 4 we get;

65\°+ \angle 4 = 180\°\\\\ \angle 4 = 180\°-65\°\\\\\angle 4= 115\°

Thus the measure of ∠4 is 115°.

For ∠5.

∠4 and ∠5 makes straight angle, and we know that the measure of straight angle is 180°.

So, we can frame this in equation form as;

\angle4 +\angle 5 =180\°

Substituting the values of of angle 4 to find angle 5 we get;

115\°+ \angle 5 = 180\°\\\\ \angle 5 = 180\°-115\°\\\\\angle 5= 65\°

Thus the measure of ∠5 is 65°.

Hence:

The measure of ∠1 is 65°.

The measure of ∠2 is 65°.

The measure of ∠3 is 50°.

The measure of ∠4 is 115°.

The measure of ∠5 is 65°.

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<h3>Given :-</h3>
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  • Pravin ran 38.6 km

\\  \\

To find :

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\\  \\

<h3>Let :</h3>

  • No. of kilometers ran by Brenda be x.

\\  \\

<h3>Solution:</h3>

\\  \\

Equation formed:-

\\  \\

Total distance covered by Pravan = More distance covered by Pravan + distance covered by Brenda.

Therefore:-

\\  \\

\leadsto \sf38.6 = 20.3 + x

Write the equation

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\leadsto \sf38.6 - 20.3 =x

When we transfer 20.3 to left side the positive sign (+) will change into negative sign (–)

\\  \\

\leadsto \sf x = 38.6 - 20.3

Arrange the equation because x is always represented at left side.

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\leadsto \boxed {\pmb{\sf x = 18.3}}\star

After subtracting 38.6 with 20.3 we will get result as 18.3 .

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\therefore \red{ \underline{  \pmb{\frak{Distance  ~ covered ~by ~Brenda~ is ~equal ~to~18.3~kilometers}}}}

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2 years ago
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