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3 years ago

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Great Granola makes a trail mix consisting of peanuts, cashews, raisins, and dried cranberries. The trail mix sells for $3.50, a

nd the most expensive ingredient is the cashew. The production manager takes a random sample of 15 bags of trail mix from two factories to determine the amount of cashews in each bag. What statistical information could be useful to the production manager? Check all that apply.

2 answers:

Arada [10]3 years ago

7 0

Answer:

the answers are A,C,D.

Leno4ka [110]3 years ago

5 0

Answer:

the answer is the average amount of cashews per bag to determine average cost

the amount of variation in ounces of cashews in the bags of trail mix

which factory produces the most consistent ounces of cashews in each bags of trail mix

Step-by-step explanation:

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Multiply ( + 2) (2 – )

Elina [12.6K]

Answer:

-4

Step-by-step explanation:

('+')('-') = ('-')

Therefore,

(+2)(-2) = (-4)

7 0

3 years ago

A rectangular garden is 6 feet long and 4 feet wide. A second rectangular garden has dimensions that are double the dimensions o

Talja [164]

Percent change is 100%

Step-by-step explanation:

Step 1: Find the perimeter of the first garden when length = 6 ft and width = 4 ft

Perimeter = 2 (length + width)

= 2 (6 + 4) = 2 × 10 = 20 ft

Step 2: Find the perimeter of the second garden when length = 12 ft and width = 8 ft (∵ dimensions are doubled)

Perimeter = 2 (12 + 8) = 2 × 20 = 40 ft

Step 3: Find the percent change in perimeter

Percent Change = Final value - initial value/Initial Value × 100

= (40 - 20/20) × 100

= 1 × 100 = 100%

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3 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

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3 years ago

Identify the slope and y-intercept of the linear equation: y = -2x - 4

Maurinko [17]

Answer:

Slope: -2

Y-intercept: -4

Step-by-step explanation:

Hope this helps. Pls give brainliest.

3 0

3 years ago

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How to write x^2 + y^2 - 2x + 2y = 7 in standard form

kodGreya [7K]

Answer:

7 is its standared form

Step-by-step explanation:

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3 years ago