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denpristay [2]
3 years ago
7

Find the slope!!! Please help!!!

Mathematics
2 answers:
jolli1 [7]3 years ago
5 0
5+5+6 then that’s your answer
pychu [463]3 years ago
5 0
I believe than is 1/4
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What values complete each statement?
aliya0001 [1]

For this case we have:

By properties of the radicals \sqrt {a} = a ^{\frac {1} {2}}

So:

(\sqrt {7}) ^ 2 = (7 ^ {\frac {1} {2}}) ^ 2.

Now, for power properties we have:

(b ^ {\frac {c} {d}}) ^ e = b ^ {\frac {c * e} {d}}

Thus, (7 ^ {\frac {1} {2}}) ^ 2 = 7 ^ {\frac {2} {2}} = 7

So:

7 ^ {\frac {1} {2}} = \sqrt {7}in its radical form

Answer:

(\sqrt {7}) ^ 2 = (7 ^ {\frac {1} {2}}) ^ 2= 7 ^ {\frac {2} {2}} = 7 in its simplest form.

7 ^ {\frac {1} {2}} = \sqrt {7}in its radical form


4 0
2 years ago
Read these sentences from the text.
chubhunter [2.5K]

Answer: Hi! I would say it is D because the other answers really don’t make sense. And the passages said that they were rated low for air quality.

Step-by-step explanation:

I hope this helps!

3 0
2 years ago
Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
zheka24 [161]
<h2>Hello!</h2>

The answer is:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

<h2>Why?</h2>

To calculate the speed of the cars, we need to write two equations in order to create a relation between the two speeds and be able to isolate one in function of the other.

So, let be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

x_{FirstCar}=x_o+v*t

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

x_{SecondCar}=x_o+(v+14mph)*t

Now, we already know that both cars met after 2 hours and 45 minutes, meaning that positions will be the same at that moment, and the distance between A and B is 264 miles,  so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph

Then, since we know that they covered a combined distance which is equal to 264 miles of distance in 2 hours + 45 minutes, we  have:

2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours

Writing the equation, we have:

264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph

We have that the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph

Hence, we have that:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

Have a nice day!

4 0
3 years ago
Read 2 more answers
Me remaining days
Alex73 [517]
Well $25 is the standard price initially.

$10 is added every hour as a constant rate.

Therefore a. 25 + 10h is the right expression
4 0
3 years ago
Solve and check: -9k+13+k=61
VARVARA [1.3K]
-8k= 48

divide 8

ANSWER: k = -6
8 0
2 years ago
Read 2 more answers
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