1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
oksian1 [2.3K]
3 years ago
7

15 points!!!

Mathematics
1 answer:
ankoles [38]3 years ago
4 0

Answer:

Step-by-step explanation:

4/15×6/14= 0.1142

You might be interested in
Priya is hosting a poetry club meeting this week and plans to have fruit punch and cheese for the meeting. She is preparing 8 ou
Sveta_85 [38]

Answer:

b= $3.99×2 + $2.50= $10.48

Step-by-step explanation:

We have the following unknowns:

p: number of people in the club

f: ounces of fruit punch

c: ounces of cheese

b: budget in dollars

We know that

p=12

Priya is preparing 8 ounces of fruit punch per person, so:

f= 8×p = 8×12 = 96

We need 96 ounces of fruit punch

Priya is preparing 2 ounces of cheese per person, so:

c= 2×p = 2×12 = 24

We need 24 ounces of cheese

A package of cheese contains 16 ounces and costs $3.99. In order to get all the cheese we need, Priya have to buy 2 packages of cheese.

2×16=32

32>24

A one-gallon jug of fruit punch contains 128 ounces and costs $2.50. Then, Priya have to buy only one gallon jug.

128>96

The budget would be:

b= $3.99×2 + $2.50×1

3 0
3 years ago
Round to the nearest thousand then subtract
grin007 [14]
6000 - 600

If u subtract dis, it would be 5400 :)
5 0
3 years ago
Read 2 more answers
2. P337. 23. A large box contains 10,000 ball bearings. A random sample of 120 is chosen. The sample mean diameter is 10 mm, and
Rashid [163]

Answer:

B is True

A, C. D are false

Step-by-step explanation:

Given :

Sample size, n = 120

Mean diameter, m = 10

Standard deviation, s = 0.24

Confidence level, Zcritical ; Z0.05/2 = Z0.025 = 1.96

The confidence interval represents how the true mean value compares to a set of values around the mean computed from a set of sample drawn from the population.

The population here is N = 10000

To obtain

Confidence interval (C. I) :

Mean ± margin of error

Margin of Error = Zcritical * s/sqrt(n)

Margin of Error = 1.96 * 0.24/sqrt(120)

Confidence interval for the 10,000 ball bearing :

10 ± 1.96 * (0.24) / sqrt(120)

Hence. The confidence interval defined as :

10 ± 1.96 * (0.24) / sqrt(120) is the 95% confidence interval for the mean diameter of the 10,000 bearings in the box.

4 0
3 years ago
Choose the best definition for the following term: variable
andrew11 [14]

Step-by-step explanation:

a variable is a quantity that may change within the context of a mathematical problem or experiment

I hope this was helpful

6 0
3 years ago
What bag is heavier 2 kilograms or 3000grams​
pav-90 [236]

3000 grams because 2 kilograms is 2000 grams and 3000 is greater than 2000

3 0
4 years ago
Read 2 more answers
Other questions:
  • What is equivalent 75/100
    8·2 answers
  • If the length of the rectangle is twice the width and the perimeter of the rectangle is 30 cm what is length and width of the re
    11·1 answer
  • A zebra eats 28 pounds of grass in a day. How many pounds of grass would 14 zebras eat in a day? A. 2 pounds B. 42 pounds C. 392
    8·2 answers
  • What is the value of (f-g)(5)
    7·2 answers
  • X+2=6x-18<br> Please help, i need to solve for x, and this is really confusing for me.
    15·2 answers
  • Show that the plane and line with the given equations intersect, and then find the acute angle of intersection between them. (Gi
    10·1 answer
  • I need answers to the questions I didn't do
    11·1 answer
  • Solve by substitution: 7x+4y=14 and x+2y=12<br> HURRY I'LL GIVE BRAINLIEST!!
    12·1 answer
  • Marking brainliest.A block of cheese is in the shape of a triangular prism. The area of the base for the block of cheese is 96
    8·1 answer
  • Find the cube of this by using formula (p - 49)​ please answerpls
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!