What would happen if Earth's weight was increased

A vessel containing 200 ml hydrogen gas at pressure 500torr at temperature 10 degree C.Find its volume when pressure increased t

Margaret [11]

Answer:

When the pressure and the temperature are increased the volume is 285.7 ml.

Explanation:

We can find the new volume by using the Ideal Gas Law:

$PV = nRT$

Where:

P: is the pressure

V: is the volume

n: is the number of moles

R: is the gas constant

T: is the temperature

Initially, when V₁ = 200 ml, P₁ = 500 torr and T₁ = 10 °C, we have:

$nR = \frac{P_{1}V_{1}}{T_{1}}$ (1)

And finally, when P₂ = 700 torr and T₂ = 20 °C, we have:

$nR = \frac{P_{2}V_{2}}{T_{2}}$ (2)

By equating (1) with (2):

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}$

$V_{2} = \frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}} = \frac{500 torr*200 ml*20 ^{\circ} C}{10 ^{\circ} C*700 torr} = 285.7 ml$

Therefore, when the pressure and the temperature are increased the volume is 285.7 ml.

I hope it helps you!

3 0

3 years ago

A proton is traveling horizontally to the right at 1.8 × 106 m/s. (a) Find the magnitude and direction of the weakest electric f

Mars2501 [29]

Answer:

528398.4375 N/C opposite to the direction of the proton

$3.56\times 10^{-8}\ s$

288.24609375 N/C in the same direction of the motion of the electron

Explanation:

t = Time taken

u = Initial velocity = 0

v = Final velocity = $1.8\times 10^{6}\ m/s$

s = Displacement = 3.2 cm

a = Acceleration

Mass of electron = $9.11\times 10^{-31}\ kg$

Mass of electron = $1.67\times 10^{-27}\ kg$

q = Charge of particle = $1.6\times 10^{-19}\ C$

$v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{0^2-(1.8\times 10^6)^2}{2\times 0.032}\\\Rightarrow a=-5.0625\times 10^{13}\ m/s^2$

Electric field is given by

$E=\dfrac{ma}{q}\\\Rightarrow E=\dfrac{1.67\times 10^{-27}\times -5.0625\times 10^{13}}{1.6\times 10^{-19}}\\\Rightarrow E=−528398.4375\ N/C$

The electric field is 528398.4375 N/C opposite to the direction of the proton

$v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{0-1.8\times 10^6}{-5.0625\times 10^{13}}\\\Rightarrow t=3.56\times 10^{-8}\ s$

The time taken is $3.56\times 10^{-8}\ s$

$E=\dfrac{ma}{q}\\\Rightarrow E=\dfrac{9.11\times 10^{-31}\times -5.0625\times 10^{13}}{-1.6\times 10^{-19}}\\\Rightarrow E=288.24609375\ N/C$

The electric field is 288.24609375 N/C in the same direction of the motion of the electron

7 0

4 years ago

Lenses can be found in a variety of objects which example does not have a lens?

Burka [1]

Tbh ! All of them have lens but I would go with B.) Smart Phone

Hope This Helps !!!

4 0

4 years ago

Read 2 more answers

What is the new pressure of 150 ml of a gas that is compressed to 50 ml when the original pressure was 3.0 atm and the temperatu

Firlakuza [10]

Answer: 9.0 atm

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

$P_1V_1=P_2V_2$