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4 years ago

A batter hits a baseball with a bat. The bat exerts a force on the ball. Does the ball exert a force on the bat?

Physics

2 answers:

pashok25 [27]4 years ago

8 0

Answer:

when batter hit the ball with bat then force is applied by the bat on the ball and same force is applied on the bat by the ball.

This is an example of action reaction law

Explanation:

As we know by newton's III law that every action has equal and opposite reaction force

Which means if a force is applied by an object to another object then the same magnitude force is applied by that object on the first one.

The force will be of same magnitude but opposite in direction

This is known as reaction force.

As per Newton's III law every action has equal and opposite reaction force on it.

So here when batter hit the ball with bat then force is applied by the bat on the ball and same force is applied on the bat by the ball.

This is an example of action reaction law

Mazyrski [523]4 years ago

3 0

Yes, think about the difference of swinging a bat and not hitting a ball. It's fairly easy right? Now, when you hit a ball with the bat, you will feel the bat sting your hands. That's the force the ball is exerting on the bat!

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What is the difference between reflection and refraction? What changes and what does not change.

wolverine [178]

Answer:

Reflection involves a change in direction of waves when they bounce off a barrier. Refraction of waves involves a change in the direction of waves as they pass from one medium to another.

Explanation:

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2 years ago

A block is on a frictionless table, on earth. The block accelerates at 7.5 m/s when a 70 N horizontal force is applied to it. Th

Liono4ka [1.6K]

Answer:

The weight of the block on the moon is 15 kg.

Explanation:

It is given that,

The acceleration of the block, a = 7.5 m/s²

Force applied to the box, F = 70 N

The mass of the block will be, $m=\dfrac{F}{a}$

$m=\dfrac{70\ N}{7.5\ m/s^2}$

m = 9.34 kg

The block and table are set up on the moon. The acceleration due to gravity at the surface of the moon is 1.62 m/s². The mass of the object remains the same. It weight W is given by :

$W=m\times g$

$W=9.34\ kg\times 1.62\ m/s^2$

W = 15.13 N

W = 15 N

So, the weight of the block on the moon is 15 kg. Hence, this is the required solution.

3 0

3 years ago

A 1100 kg car rounds a curve of radius 68 m banked at an angle of 16 degrees. If the car is traveling at 95 km/h, will a frictio

Mariulka [41]

Answer:

Yes. Towards the center. 8210 N.

Explanation:

Let's first investigate the free-body diagram of the car. The weight of the car has two components: x-direction: towards the center of the curve and y-direction: towards the ground. Note that the ground is not perpendicular to the surface of the Earth is inclined 16 degrees.

In order to find whether the car slides off the road, we should use Newton's Second Law in the direction of x: F = ma.

The net force is equal to $F = \frac{mv^2}{R} = \frac{1100\times (26.3)^2}{68} = 1.1\times 10^4~N$

Note that 95 km/h is equal to 26.3 m/s.

This is the centripetal force and equal to the x-component of the applied force.

$F = mg\sin(16) = 1100(9.8)\sin(16) = 2.97\times10^3$

As can be seen from above, the two forces are not equal to each other. This means that a friction force is needed towards the center of the curve.

The amount of the friction force should be $8.21\times 10^3~N$

Qualitatively, on a banked curve, a car is thrown off the road if it is moving fast. However, if the road has enough friction, then the car stays on the road and move safely. Since the car intends to slide off the road, then the static friction between the tires and the road must be towards the center in order to keep the car in the road.

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3 years ago

Why are Watson’s experiments considered controversial?

iris [78.8K]

D, it is considered unethical today

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3 years ago

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OLga [1]

Answer:

$\theta = 106.3 degree$