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3 years ago

A batter hits a baseball with a bat. The bat exerts a force on the ball. Does the ball exert a force on the bat?

Physics

2 answers:

pashok25 [27]3 years ago

8 0

Answer:

when batter hit the ball with bat then force is applied by the bat on the ball and same force is applied on the bat by the ball.

This is an example of action reaction law

Explanation:

As we know by newton's III law that every action has equal and opposite reaction force

Which means if a force is applied by an object to another object then the same magnitude force is applied by that object on the first one.

The force will be of same magnitude but opposite in direction

This is known as reaction force.

As per Newton's III law every action has equal and opposite reaction force on it.

So here when batter hit the ball with bat then force is applied by the bat on the ball and same force is applied on the bat by the ball.

This is an example of action reaction law

Mazyrski [523]3 years ago

3 0

Yes, think about the difference of swinging a bat and not hitting a ball. It's fairly easy right? Now, when you hit a ball with the bat, you will feel the bat sting your hands. That's the force the ball is exerting on the bat!

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A hockey puck moving at 0.4600 m/s collides with another puck that was at rest. The pucks have equal mass. The first puck is def

Sladkaya [172]

Answer:

Speed =0.283m/ s

Direction = 47.86°

Explanation:

Since it is a two dimensional momentum question with pucks having the same mass, we derive the momentum in xy plane

MU1 =MU2cos38 + MV2cos y ...x plane

0 = MU2sin38 - MV2sin y .....y plane

Where M= mass of puck, U1 = initial velocity of puck 1=0.46, U2 = final velocity of puck 1 =0.34, V2 = final velocity of puck 2, y= angular direction of puck2

Substitute into equation above

.46 = .34cos38 + V2cos y ...equ1

.34sin38 = V2sin y...equ2

.19=V2cos Y...x

.21=V2sin Y ...y

From x

V2 =0.19/cost

Sub V2 into y

0.21 = 0.19(Sin y/cos y)

1.1052 = tan y

y = 47.86°

Sub Y in to x plane equ

.19 = V2 cos 47.86°

V2=0.283m/s

7 0

2 years ago

a car moving east at 45 km/h turns and travels west at 30 km/h. What is the magnitude and direction of the change in velocity?

PSYCHO15rus [73]

Magnitude of change is 15km/h
change in direction is to the right?

3 0

2 years ago

Read 2 more answers

William Tell shoots an apple from his son's head. The speed of the 102-g arrow just before it strikes the apple is 26.7 m/s, and

xxMikexx [17]

To develop the problem, we require the values concerning the conservation of momentum, specifically as given for collisions.

By definition the conservation of momentum tells us that, $m_1V_1+m_2V_2 = (m1+m2)V_f$

To find the speed at which the arrow impacts the apple we turn to the equation of time, in which,

$t= \sqrt{\frac{2h}{g}}$

The linear velocity of an object is given by

$V=\frac{X}{t}$

Replacing the equation of time we have to,

$V_f = \frac{X}{t}\\V_f =\frac{X}{\sqrt{\frac{2h}{g}}}\\V_f = \frac{6.9}{\sqrt{\frac{2(1.85)}{9.8}}}\\V_f = 11.23m/s$

Velocity two is neglected since there is no velocity of said target before the collision, thus,

$m_1V_1 = (m1+m2)V_f$

Clearing for m_2

$m_2 = \frac{m_1V_1}{V_f}-m_1\\m_2 = \frac{(0.102)(26.7)}{11.23}-0.102\\m_2 = 0.1405KG= 140.5g$

8 0

2 years ago

Which law does this diagram illustrate?

kirill115 [55]

Here, the diagram shows Kepler's first law of Planetary motion, which tells, "<span>A line segment joining a planet and the Sun sweeps out equal areas during equal intervals of time".

In short, Your Answer would be Option D

Hope this helps!</span>

6 0

2 years ago

Read the intro to lab 10. We are going to assume that the experiment was done in a styrofoam cup, so we are not going to include

artcher [175]

Answer:

e% = 3.4%

Explanation:

This is a calorimetry problem where the heat released equals the heat absorbed

m $c_{e1}$ (T₀ - T_f) = M c_{e2} (T₁ - T_f)

Index 1 refers to water and index 2 to metal, in this case it asks for the specific heat of the metal (c_{e2})

c_{e2} = m / M c_{e1} (T_f -T₀) / (T₁ - T_f)

Let's calculate

c_{e} = 60/100 4.19 (24-20) / (100-24)

c_{e2} = 0.1323 j / gC

This metal is possibly lead, which is its specific heat is 0.128 J / gC

The percentage error is

e% = (c_{e2} - 0.128) /0.128 100

e% = 3.4%

8 0

2 years ago