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guapka [62]
3 years ago
6

A batter hits a baseball with a bat. The bat exerts a force on the ball. Does the ball exert a force on the bat?

Physics
2 answers:
pashok25 [27]3 years ago
8 0

Answer:

when batter hit the ball with bat then force is applied by the bat on the ball and same force is applied on the bat by the ball.

This is an example of action reaction law

Explanation:

As we know by newton's III law that every action has equal and opposite reaction force

Which means if a force is applied by an object to another object then the same magnitude force is applied by that object on the first one.

The force will be of same magnitude but opposite in direction

This is known as reaction force.

As per Newton's III law every action has equal and opposite reaction force on it.

So here when batter hit the ball with bat then force is applied by the bat on the ball and same force is applied on the bat by the ball.

This is an example of action reaction law

Mazyrski [523]3 years ago
3 0
Yes, think about the difference of swinging a bat and not hitting a ball. It's fairly easy right? Now, when you hit a ball with the bat, you will feel the bat sting your hands. That's the force the ball is exerting on the bat!
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According to quantum physics, measuring velocity of a tiny particle with an electromagnet
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Answer:

Option A.

Explanation:

In quantum physics <u>there is a law to relate the position and the momentum of the particle</u>, it says that if we know with precision where is a quantum particle, we can not know the momentum of this particle, in other words, the velocity of the particle. So, when we measure the velocity of the particle we find the correct value of the particle, but we can not determine with accuracy where is the particle. This law is known as the Heisenberg's uncertainty principle and, its expressed as follows:    

\Delta x \Delta p \geq \frac{h}{4 \pi}

<em>where Δx: is the position's uncertainty, Δp: is the momentum's uncertainty and h: is the Planck constant.</em>  

Therefore, the correct answer is A: measuring the velocity of a tiny particle with an electromagnet has no effect on the velocity of the particle. It only affects the determination of the particle's position.      

I hope it helps you!

4 0
2 years ago
You discover a binary star system in which one member is a15 solar mass main-sequence star and the other star is a 10 solar mass
Trava [24]

Answer:

yes

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3 years ago
How does an object's acceleration change if the net
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C.the acceleration is doubled
5 0
2 years ago
I need help with this
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While ice melts, it remains at 0 °C, and the liquid water that is formed with the latent heat of fusion is also at 0 °C. The heat of fusion for water at 0 °C is approximately 334 joules per gram, and the heat of vaporization at 100 °C is about 2,230 joules per gram. So it will be C

7 0
3 years ago
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A 150kg person stands on a compression spring with spring constant 10000n/m and nominal length of 0.50.what is the total length
Ivahew [28]

Answer:

<em>The total length of the spring would be 0.65 m</em>

Explanation:

The Concept

Hooke's law evaluates the increment of  spring in relation to the force acting on the body. Hooke's law states that for a spring undergoing deformation, the  force applied is directly proportional to the deformation experienced by the spring. Hooke's law is represented thus;

F = k x ..................1

where F is the force applied to the spring

k is the spring constant

x is the spring stretch or extension

Step by Step Calculations

We have to obtain x before adding it to the nominal length, We make x the subject formula in equation 1;

x = F/k

but F = m x g

so, x = (m x g)/k

given that, the mass of the person m =150 kg

g is the acceleration due to gravity = 9.81 m/s^{2}

k is the spring constant = 10000 N/m

then x = (9.81 m/s^{2} x 150 kg)/10000 N/m

x = 0.14715 m

the extension experienced by the spring after the compression is 0.14715 m

The total length of the spring would be;

L = 0.14715 m + 0.5 m = 0.64715

L ≈  0.65 m

Therefore the total length of the spring would be 0.65 m

4 0
3 years ago
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