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Juli2301 [7.4K]
4 years ago
11

Name 15 measurement instrument use in physic and their uses

Physics
1 answer:
zlopas [31]4 years ago
7 0

1. Meter Rule  

Meter rule is used to measure the small length or distance between any two points.

2. Measuring Tape

It is also use to measure length and distance in meters and centimeters.

3. Vernier calipers.

It can be use to measure small diameter or radius of objects up-to 10th part of a millimeter.

4. Micrometer screw gauge.

It is also use to measure diameter or radius unto 100th part of a millimeter.

5.Beam balance

It is use to measure mass upto 10th part of a gram.

6. Physical balance

it is use to measure mass upto 100th part of a gram.

7.Electronic balance

It is use to measure mass upto 100th part of a gram.

8. Stop watch.

It is use to measure time upto 10th and 100th part of a second.

9.Measuring cylinder

It is use to measure volume of a small object.

10. Hydrometer

It is use to measure density of liquids.

11. Barometer.

It is use to measure the atmospheric pressure.

12. Thermometer

It is use to measure temperature.

13. Ammeter

It is used to measure amount of electric current in circuit.

14.Photometer.

It is use to measure intensity of light.

15. Protector,.

It can be use to measure angle.

16. Lactometer.

It can be use to measure specific gravity of milk.

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<span>therefore draw it linear first. F ---- O-----F </span>
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<span>Therefore 3 lone pairs on each F and 2 lone pair on O. </span>
<span>If you check for formal charges, all the atoms are neutral </span>
<span>F will have 3 lone pairs + 1 bond = 7 electrons (bond = 1/2 electron for formal charge distribution) therefore both the F's are neutral </span>
<span>Now look at the O: it should have 6.. it has two lone pair and 2 bonds = 4 electrons and 2 bonds = 1 electron each = 2 electrons from bonds = 6 total electrons for formal charge which is exactly the # it should have. There is no need for any double bond in this as there are no charges to be separated. </span>
<span>Now if u look at the # of domains around O you will see if you include the lone pairs it has a sp3 hybridization (4 domains) therefore a tetrahedron which has 2 lone pairs and 2 bonds.. since there are two lone pairs, the lone pair/bond pair repulsion is so high it is going to repel the two Fluorines and form a bent structure, looks a lot like H2O. </span>
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Answer:true

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Answer:

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Explanation:

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¢ = ∆L/L1∆°C

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Where ∆L is the change in length = L2-L1

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∆°C is the change in temperature = °C2 - °C1 = 50-(-30) = 80°C

Substituting this values inside the formula to get the final length L2 after expansion, we have;

12 x 10⁻⁶ °C⁻¹ = L2-12/12×80

12 x 10⁻⁶ °C⁻¹ = L2-12/960

L2-12= 960×12 x 10⁻⁶ °C⁻¹

L2-12 = 0.001152

L2 = 12+0.001152

L2 = 12.001152m

Expansion will be the change in length L2-L1 = 12.001152-12

= 0.001152m

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<span>Compressional stress</span>
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