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3 years ago

Name 15 measurement instrument use in physic and their uses

Physics

1 answer:

zlopas [31]3 years ago

7 0

1. Meter Rule

Meter rule is used to measure the small length or distance between any two points.

2. Measuring Tape

It is also use to measure length and distance in meters and centimeters.

3. Vernier calipers.

It can be use to measure small diameter or radius of objects up-to 10th part of a millimeter.

4. Micrometer screw gauge.

It is also use to measure diameter or radius unto 100th part of a millimeter.

5.Beam balance

It is use to measure mass upto 10th part of a gram.

6. Physical balance

it is use to measure mass upto 100th part of a gram.

7.Electronic balance

It is use to measure mass upto 100th part of a gram.

8. Stop watch.

It is use to measure time upto 10th and 100th part of a second.

9.Measuring cylinder

It is use to measure volume of a small object.

10. Hydrometer

It is use to measure density of liquids.

11. Barometer.

It is use to measure the atmospheric pressure.

12. Thermometer

It is use to measure temperature.

13. Ammeter

It is used to measure amount of electric current in circuit.

14.Photometer.

It is use to measure intensity of light.

15. Protector,.

It can be use to measure angle.

16. Lactometer.

It can be use to measure specific gravity of milk.

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An archer shoots an arrow 75 m distant target; the bull's-eye of the target is at the same height as the release height of the a

Liono4ka [1.6K]

Answer:

$16.25^{\circ}$

Explanation:

R = Horizontal range of projectile = 75 m

v = Velocity of projectile = 37 m/s

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

Horizontal range is given by

$R=\dfrac{v^2\sin2\theta}{g}\\\Rightarrow \theta=\dfrac{\sin^{-1}\dfrac{Rg}{v^2}}{2}\\\Rightarrow \theta=\dfrac{\sin^{-1}\dfrac{75\times 9.81}{37^2}}{2}\\\Rightarrow \theta=16.25^{\circ}$

The angle at which the arrow is to be released is $16.25^{\circ}$ .

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3 years ago

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2 years ago

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A 91.5 kg football player running east at 3.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity aft

PIT_PIT [208]

Their velocity afterward is v=3.467 m/s

Explanation:

Given:

Mass of the first football player= 91.5 kg

Initial velocity of the football player 3.73 m/s

Mass of second football player=63.56 kg

Initial velocity of the second football player=3.09 m/s

To find:

Final velocity of both players=?

Solution:

According to the law of conservation of momentum,

Initial momentum =final momentum

mathematically represented as

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$ ...........................(1)

where

$u_1$ =intial velocity of the football player

$u_2$ = inital velocity of second football player

$v_1$ =finall velocity of the first football player

$v_2$ =final velocity of second football player

after tackling , both the football players moves with the same velocity,

so $v_1=v_2=v$

Hence equation (1) becomes

$m_1u_1+m_2u_2=(m_1+m_2)v$

$v=\frac{m_1u_1+m_2u_2}{(m_1+m_2)}$

now substituting the values,

$v=\frac{(91.5\times+3.73)+(63.5\times3.09)}{(91.5+63.5)}$ $v=\frac{(341.29+196.210)}{155}$

$v=\frac{537.5}{155}$

v=3.467 m/s

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3 years ago

Calculate the power of an engine which can supply 60kg of energy per minute

Nutka1998 [239]

Answer:

1 Watt

Explanation:

Power (P) = w / Δt

w = work done

Δt = change in time

Power (P) = 60kg / 60 seconds

Power (P) = 1 Watt

6 0

3 years ago

The restoring force on a pendulum bob is proportional to sin(θ), where θ is the angle which the pendulum makes with the vertical

anyanavicka [17]

Answer:

The angle is 4.44º

Explanation:

If:

$\frac{sin\theta -\theta}{\theta } \leq 0.1o/o\\\frac{sin\theta -\theta}{\theta }\leq 10^{-3}$

According the Taylor`s series:

$sin\theta =\theta -\frac{\theta ^{3} }{3!} ....$

$\frac{\theta ^{2} }{6} \leq 10^{-3} \\\theta ^{2} \leq 6x10^{-3} \\\theta \leq \sqrt{6x10^{-3} } \\\theta \leq 0.0775\\\theta = 0.0775rad=4.44$

8 0

3 years ago