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MAXImum [283]
3 years ago
8

Describe a scenario where a car's speed could stay the same, but the acceleration changes.

Physics
1 answer:
k0ka [10]3 years ago
8 0

Answer:

An object's acceleration is the rate its velocity (speed and direction) changes. Therefore, an object can accelerate even if its speed is constant - if its direction changes.

Explanation:

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How does the theory of relativity explain the gravity exerted by massive objects?
Maslowich

(D)

Explanation:

The more massive an object is, the greater is the curvature that they produce on the space-time around it.

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3 years ago
Which layer in the image above represents the layer of the Earth composed of liquid metal? *
weeeeeb [17]

Answer:

4

Explanation:

5 0
2 years ago
Light of wavelength 633 nm from a He-Ne laser passes through a circular aperture and is observed on a screen 4.0 m behind the ap
Verizon [17]

Answer:

The answer is "1.144 \times 10^{-4} \ m".

Explanation:

w=\frac{2.44 \lambda L}{D}\\\\D=\frac{2.44 \lambda L}{w}\\\\

   =\frac{2.44 \times 633 \times 10^{-9}\times 4 }{0.054}\\\\=\frac{6178.08\times 10^{-9}}{0.054}\\\\=1.144 \times 10^{-4} \ m

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3 years ago
A spring with force constant of 59 N/m is compressed by 1.3 cm in a hockey game machine. The compressed spring is used to accele
Furkat [3]

Answer:

The puck moves a vertical height of 2.6 cm before stopping

Explanation:

As the puck is accelerated by the spring, the kinetic energy of the puck equals the elastic potential energy of the spring.

So, 1/2mv² = 1/2kx² where m = mass of puck = 39.2 g = 0.0392 g, v = velocity of puck, k = spring constant = 59 N/m and x = compression of spring = 1.3 cm = 0.013 cm.

Now, since the puck has an initial velocity, v before it slides up the inclined surface, its loss in kinetic energy equals its gain in potential energy before it stops. So

1/2mv² = mgh where h = vertical height puck moves and g = acceleration due to gravity = 9.8 m/s².

Substituting the kinetic energy of the puck for the potential energy of the spring, we have

1/2kx² = mgh

h = kx²/2mg

= 59 N/m × (0.013 m)²/(0.0392 kg × 9.8 m/s²)

= 0.009971 Nm/0.38416 N

= 0.0259 m

= 2.59 cm

≅ 2.6 cm

So the puck moves a vertical height of 2.6 cm before stopping

3 0
3 years ago
What is the only thing that can pull a beam of light towards itself ? ​
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Answer:

<h2><em>The </em><em>only </em><em>thing</em><em> </em><em>that</em><em> </em><em>can</em><em> </em><em>pull</em><em> </em><em>a </em><em>beam </em><em>of</em><em> light</em><em> </em><em>towards</em><em> </em><em>it</em><em> </em><em>self</em><em> </em><em>is </em><em>a </em><em>black </em><em>hole.</em></h2>

4 0
2 years ago
Read 2 more answers
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