Question

g At 4 ft. from a point source of gamma radiation the intensity is 158 mRem/hr. How far away would you have to move to decrease the intensity to 17 mRem/hr.? [I1/I2 = (D2)2/(D1)2] I1(D1)2 = I2(D2)2

Answer 1

Answer:

You will have to move 12.2 ft to decrease the initial intensity to 17 mRem/h.

Explanation:

The distance can be calculated using the following equation:

$\frac{I_{1}}{I_{2}} = \frac{D_{2}^{2}}{D_{1}^{2}}$

Where:

I₁ = 158 mRem/h

I₂ = 17 mRem/h

D₁ = 4 ft.

D₂=?

Hence, the distance D₂ is:

$D_{2} =\sqrt{\frac{I_{1}}{I_{2}}*D_{1}^{2}} = \sqrt{\frac{158 mRem/h}{17 mRem/h}*(4 ft)^{2}} = 12.2 ft$

Therefore, you will have to move 12.2 ft to decrease the initial intensity to 17 mRem/h.

I hope it helps you!