Ask question

Ask question

All categories

3 years ago

10

Dr. Perez is part of a team of researchers who are working on designing and building a probe to study solar flares what conditio

n must the probe meet

2 answers:

vovangra [49]3 years ago

7 0

Solar flares are bright, high-energy rays from the sun. Once it is intense enough, it can affect the Earth with penetrating radiation. Having this knowledge, probes that study or document for these solar flares near the sun's atmosphere should be able to resist high temperatures and high radiation using certain insulators and light materials suitable for space monitoring.

gavmur [86]3 years ago

7 0

Answer:It must be able to withstand a temperature of up to 20 million degrees Celsius

Explanation:

You might be interested in

A double nozzle lying in a horizontal x-y plane discharges water into the atmosphere at a rate of 0.5 m3 /s. Assume the water sp

Kisachek [45]

Answer:

The force is $F= 46.25kN$

Explanation:

The diagram for this question is shown on the first uploaded image

At Equilibrium the summation of the of force on the vertical axis is zero

i.e $\sum F_y =0$

=> $F_y sin \ 60^o =\rho Q (v_2 -v_1 cos \ 30^o)$

$v_2$ is the is the speed of water at the nozzle which can be mathematically evaluated as

$v_2 = \frac{R}{A_n}$

substituting $0.5m^3/s$ for R and $\frac{\pi}{4}(12*\frac{1m}{100} )^2$ for $A_n$

$v_2 = \frac{0.5}{\frac{\pi}{4} * (12*\frac{1}{100} )^2 }$

$= 44.23 m/s$

$v_1$ is the is the speed of water at the pipe which can be mathematically evaluated as

$v_1 = \frac{R}{A_p}$

substituting $0.5m^3/s$ for R and $\frac{\pi}{4}(30*\frac{1m}{100} )^2$ for $A_p$

$v_1 = \frac{0.5}{\frac{\pi}{4} * (30*\frac{1}{100} )^2 }$

$= 7.07 m/s$

$\rho$ is he density of water with value $\rho =1000 kg /m^3$

Substituting values into the equation above

$F_ysin 60^o = 1000 (0.5) (44.23 -7.07 cos 30)$

$= 21.99kN$

At Equilibrium the summation of the of force on the horizontal axis is zero

i.e $\sum F_x =0$

=> $F_y sin \ 30^o =\rho Q (v_2 -v_1 sin \ 30^o)$

Since The speed at both A and B nozzle are the same then $v_2$ remains the same

Substituting values

$F_x sin30^o =1000 (0.5) (44.23 - 7.07*sin30)$

=> $F_x = 40.69kN$

Hence the force acting on the flange bolts required to hold the nozzle in place is

$F = \sqrt{F_x^2 + F_y^2}$

$= \sqrt{40.69 ^2 + 21.99^2}$

$F= 46.25kN$

6 0

3 years ago

Read 2 more answers

PLEASE HLEP I WILL GIVE BRAINLIEST TO CORRECT ANSWER!!!!!!

Hoochie [10]

Answer:

75 km/h

Explanation:

Speed = Distance divided by Time.

The train went a distance of 300 km in 4 hours. Therefore, the speed of the train is: 300 divided by 4 = 75 km/h

8 0

3 years ago

Read 2 more answers

A 2-Newton upward net force is being applied to a 10-kg object. What is the magnitude of the upward

Colt1911 [192]

Acceleration in m/s^2 = 2/10 = 0.2 m/s^2

7 0

3 years ago

Which method of testing substances is a sure way to identify a chemical reaction?

Sergeu [11.5K]

Answer:

B

Explanation:

That's the answer. Hope it helped!

7 0

2 years ago

You want to raise the temperature of 22kg of water from 60°C to 95°C. If electricity costs $0.08/kWh, how much would it cost you

Sladkaya [172]

Answer:

dgtgh

Explanation:

dgdfhdhfffff thdhfghjfj e

3 0

3 years ago