18,055
-
3,138
———-
14,927
14,927
+
18,055
———-
32,982
1) 1 1/6
2) 1 1/6
4) 5 1/ 18
hope you got your answer i didn't know what number 3 was so i did the rest
Answer:
Gila Monster is 1.54 times that of Chuckwalla.
Step-by-step explanation:
Given:
Average Length of Gila Monster = 0.608 m
Average Length of Chuckwalla = 0.395 m
We need to find the number of times the Gila monster is as the Chuckwalla.
Solution:
Now we know that;
To find the number of times the Gila monster is as the Chuckwalla we will divide the Average Length of Gila Monster by Average Length of Chuckwalla.
framing in equation form we get;
number of times the Gila monster is as the Chuckwalla = 
Rounding to nearest hundredth's we get;
number of times the Gila monster is as the Chuckwalla = 1.54
Hence Gila Monster is 1.54 times that of Chuckwalla.
Solve it by finding out how many times 22 can be put into 22, which is once, so the answer is 1.