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3 years ago

What is the total area

Mathematics

2 answers:

MariettaO [177]3 years ago

7 0

Correct me if I’m wrong but I believe the answer is 40.

garik1379 [7]3 years ago

6 0

Answer: 68

I write down the solution below

Good luck :)

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One of the altitudes of the parallelogram shown is StartRoot 22.5 EndRoot units. What is the length of the other altitude?

aksik [14]

Answer:

the length of the other altitude of the given parallelogram will be 6 units and option B is the correct choice.

6 0

3 years ago

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Ico

Anna [14]

Answer:

a = 6

Step-by-step explanation:

-6(2 + a) = -48

it is basically 2 steps

Divide by -6 first

(2 + a) = -48 / -6

2 + a = 8

minus the 2

a =6

5 0

3 years ago

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HELP PLEASE FAST. 30 POINTS.

QveST [7]

Answer:

<em>The age of the oldest child id 7.</em>

Step-by-step explanation:

There are 5 children:

1st Child: 7 Years Old

2nd Child: 6 Years Old

3rd Child: 5 Years Old

4th Child: 4 Years Old

5th Child: 3 Years Old

<em>The ges of any two consecutive children difference is 2 years old: 1st Child and 3rd Child. </em>

Hope this helped! :-)

3 0

4 years ago

Derek bought a package of 8 tennis balls. The total weight of the tennis balls was 18 ounces. How much did each tennis ball weig

beks73 [17]

2.25 ounces...18/8=2.25

7 0

3 years ago

Which of the following are identities? Check all that apply

Natasha2012 [34]

Answer:

A, C

Step-by-step explanation:

Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.

Examining

A) True

$\frac{1-tan^{2}x}{2tanx} =\frac{1}{tan2x} \\ \frac{1-tan^{2}x}{2tanx} =\frac{1}{\frac{2tanx}{1-tan^{2}x}}\\ tan2x=\frac{1-tan^{2}x}{2tanx}$

Double angle $tan2\alpha =\frac{1 -tan^{2}\alpha }{2tan\alpha}$

B) False,

No further development towards a Trig Identity

C) True

Double Angle Sine Formula $sin2\alpha =2sin\alpha *cos\alpha$

$sin(8x)=2sin(4x)cos(4x)\\2sin(4x)cos(4x)=2sin(4x)cos(4x)$

D) False No further development towards a Trig Identity

$[sin(x)-cos(x)]^{2} =1+sin(2x)\\ sin^{2} (x)-2sin(x)cos(x)+cos^{2}x=1+2sinxcosx\\ \\sin^{2} (x)+cos^{2}x=1+4sin(x)cos(x)$

7 0

4 years ago

Read 2 more answers