Since there are 26 students in Mr. Carson's class, and each kid gets 3 pencils, that means we will multiply 26 and 3, in which we get 78. Now, since boxes of pencils only contain a dozen, which is 12 pencils, we will divide 78 by twelve, in which we get 6.5 boxes. You can't buy half a box, so he will need 7 boxes, since having 6 boxes means that you don't have enough pencils.
Hope this helps!
The car's average rate is 43.7 mph. The bicycle's average rate is 12.3 mph.
To get this solution, let the bicycle's average rate be (x) and the car's average rate be (x + 31.4) mph.
Distance= Speed x Time
364 = (x + x + 31.4) 6.5
364 = (2x + 31.4) 6.5
364/6.5 = 2x + 31.4
56 = 2x + 31.4
56 - 31.4 = 2x
24.6 = 2x
24.6/2 = x
12.3 = x
x = 12.3 mph
x+31.4 = 43.7 mph
Answer:
(4,0)
Step-by-step explanation:
we have
----> inequality A
----> inequality B
we know that
If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)
Verify each ordered pair
case 1) (4,0)
<em>Inequality A</em>
----> is true
<em>Inequality B</em>
----> is true
so
the ordered pair makes both inequalities true
case 2) (1,2)
<em>Inequality A</em>
----> is not true
so
the ordered pair not makes both inequalities true
case 3) (0,4)
<em>Inequality A</em>
----> is not true
so
the ordered pair not makes both inequalities true
case 4) (2,1)
<em>Inequality A</em>
----> is true
<em>Inequality B</em>
----> is not true
so
the ordered pair not makes both inequalities true
Answer:
5X + 8Y >= 300; intersection at (-20, 50)
Step-by-step explanation:
let t = work hours
0 < t < 30
X = time lawn mowing
Y = time babysitting.
X + Y < 30
5X + 8Y >= 300
We could solve...
X < 30 - Y
5(30 - Y) + 8Y >=300
150 - 5Y + 8Y >= 300
3Y >=150
Y >=50
then X < -20
intersection at (-20, 50)
