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In-s [12.5K]
3 years ago
9

Lena paid $18.96 for 3 pounds of coffee. How many pounds of coffee could she buy for $1.00

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
6 0

Answer:

0.16 pounds

Step-by-step explanation:

Lena paid $18.96 for 3 pounds of coffee.

$1.00 will make (1x3)/18.96= 3/18.96 = 0.1582278481 pounds = 0.16 pounds

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Jeff said his City got 11/3 inches of snow.write this fraction as a mixed number
olchik [2.2K]
11 is divisible by three three times with a remainder of two so the mixed number would be 3 2/3<span />
6 0
3 years ago
Read 2 more answers
1. (a). A police car, approaching right-angled intersection from the north, is chasing a speedmg
tamaranim1 [39]

Answer:

<em>The SUV is running at 70 km/h</em>

Step-by-step explanation:

<u>Speed As Rate Of Change </u>

The speed can be understood as the rate of change of the distance in time. When the distance increases with time, the speed is positive and vice-versa. The instantaneous rate of change of the distance allows us to find the speed as a function of time.

This is the situation. A police car is 0.6 Km above the intersection and is approaching it at 60 km/h. Since the distance is decreasing, this speed is negative. On the other side, the SUV is 0.8 km east of intersection running from the police. The distance is increasing, so the speed should be positive. The distance traveled by the police car (y) and the distance traveled by the SUV (x) form a right triangle whose hypotenuse is the distance between them (d). We have:

d=\sqrt{x^2+y^2}

To find the instant speeds, we need to compute the derivative of d respect to the time (t). Since d,x, and y depend on time, we apply the chain rule as follows:

\displaystyle d\ '=\frac{x.x'+y.y'}{\sqrt{x^2+y^2}}

Where x' is the speed of the SUV and y' is the speed of the police car (y'=-60 km/h)

We'll compute  :

d=\sqrt{(0.8)^2+(0.6)^2}=\sqrt{0.64+0.36}

d=1\ km

We know d'=20 km/h, so we can solve for x' and find the speed of the SUV

\displaystyle \frac{x.x'+y.y'}{\sqrt{x^2+y^2}}=20

Thus we have

x.x'+y.y'=20

Solving for x'

\displaystyle x'=\frac{20-y.y'}{x}

Since y'=-60

\displaystyle x'=\frac{20+0.6(60)}{0.8}

x'=70\ km/h

The SUV is running at 70 km/h

7 0
3 years ago
Solve the following system of equations. What is one x-value of a solution?
gulaghasi [49]

Answer:

There is some mistake in the question, because the solutions are x = -1.445 and x = -34.555

Step-by-step explanation:

Given the functions:

f(x) = x² + 4x + 10

g(x) = -32x - 40

we want to find the points at which f(x) = g(x).

x² + 4x + 10 = -32x - 40

x² + 4x + 10 + 32x + 40 = 0

x² + 36x + 50 = 0

Using quadratic formula:

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x = \frac{-36 \pm \sqrt{36^2-4(1)(50)}}{2(1)}

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x_1 = -1.445

x_2 = \frac{-36 - 33.11}{2}

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Scilla [17]
The answer would be -18°F at 6AM
Hope this helps ?(:
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2 years ago
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What is the answer to 3(m-1)=5m +3 - 2m
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Is there a answer for m what is m
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3 years ago
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