Answer:
Resulting heat generation, Q = 77.638 kcal/h
Given:
Initial heat generation of the sphere,
Maximum temperature,
Radius of the sphere, r = 0.1 m
Ambient air temperature, = 298 K
Solution:
Now, maximum heat generation, is given by:
(1)
where
K = Thermal conductivity of water at
Now, using eqn (1):
max. heat generation at maintained max. temperature of 360 K is 24924
For excess heat generation, Q:
where
Now, 1 kcal/h = 1.163 W
Therefore,
Explanation:
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Answer:
the isentropic efficiency of turbine is 99.65%
Explanation:
Given that:
Mass flow rate of LNG m = 20 kg/s
The pressure at the inlet = 3000 kPa
turbine temperature at the inlet = ( -160+273)K = 113K
The pressure at the turbine exit = 300 kPa
Power produced by the turbine W = 120 kW
Density of LNG
The formula for the workdone by an ideal turbine can be expressed by:
We all know that density = mass * volume i.e
Then ;
replacing it into the above previous derived formula; we have:
However ; the isentropic efficiency of turbine is given by the relation:
99.65%
Therefore, the isentropic efficiency of turbine is 99.65%
Answer:
hello below is missing piece of the complete question
minimum size = 0.3 cm
answer : 0.247 N/mm2
Explanation:
Given data :
section span : 10.9 and 13.4 cm
minimum load applied evenly to the top of span : 13 N
maximum load for each member ; 4.5 N
lets take each member to be 4.2 cm
Determine the max value of P before truss fails
Taking average value of section span ≈ 12 cm
Given minimum load distributed evenly on top of section span = 13 N
we will calculate the value of by applying this formula
= = 1.56 * 10^-5
next we will consider section ; 4.2 cm * 0.3 cm
hence Z (section modulus ) = BD^2 / 6
= ( 0.042 * 0.003^2 ) / 6 = 6.3*10^-8
Finally the max value of P( stress ) before the truss fails
= M/Z = ( 1.56 * 10^-5 ) / ( 6.3*10^-8 )
= 0.247 N/mm2