Answer:
A)
- Q ( kw ) for vapor = -1258.05 kw
- Q ( kw ) for liquid = -1146.3 kw
B )
- Q ( kj ) for vapor = -1258.05 kJ
- Q ( KJ ) for liquid = - 1146.3 KJ
Explanation:
Given data :
45.00 % mole of methane
55.00 % of ethane
attached below is a detailed solution
A) calculate - Q(kw)
- Q ( kw ) for vapor = -1258.05 kw
- Q ( kw ) for liquid = -1146.3 kw
B ) calculate - Q ( KJ )
- Q ( kj ) for vapor = -1258.05 kJ
- Q ( KJ ) for liquid = - 1146.3 KJ
since combustion takes place in a constant-volume batch reactor
I’m pretty sure the answer is the engine needs to be checked right away
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Answer:
critical stress 
= 1382.67 MPa
Explanation:
given data
plane strain fracture toughness = 54.8 MP
length of surface creak = 0.5 mm
we take here
parameter Y = 1.0
solution
we apply critical stress formula that is
critical stress = 
.............................1
here K is design stress plane strain fracture toughness and a is length of surface creak so put all these value in equation 1
critical stress = 
solve it we get
critical stress = 1382.67 MPa
As exposed stress 1030 MPa is less than critical stress 1382 MPa
so that fracture will not be occur here
