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hichkok12 [17]
4 years ago
13

What is poop made out of

Engineering
2 answers:
Lady_Fox [76]4 years ago
7 0

Answer: Food

Explanation:

spayn [35]4 years ago
4 0
Digested food and other waste
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What is an automotive system in relation to a vehicle’s structure and operation?
Julli [10]
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Automotive System. A group of related parts that perform a specific function. Body and Chassis System. Body, frame, suspension, steering, braking which support, stop and enclose the parts of the car.
7 0
1 year ago
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Neon is compressed from 100 kPa and 20◦C to 500 kPa in an isothermal compressor. Determine the change in the specific volume and
PIT_PIT [208]

Answer:

The specific volume is reduced in 80 per cent due to isothermal compression.

Specific enthalpy remains constant.

Explanation:

Let suppose that neon behaves ideally, the equation of state for ideal gases is:

P\cdot V = n\cdot R_{u}\cdot T

Where:

P - Pressure, measured in kilopascals.

V - Volume, measured in cubic meters.

n - Molar quantity, measured in kilomoles,

T - Temperature, measured in kelvins.

R_{u} - Ideal gas constant, measured in \frac{kPa\cdot m^{3}}{kmol\cdot K}.

On the other hand, the molar quantity (n) and specific volume (\nu), measured in cubic meter per kilogram, are defined as:

n = \frac{m}{M} and \nu = \frac{V}{m}

Where:

m - Mass of neon, measured in kilograms.

M - Molar mass of neon, measured in kilograms per kilomoles.

After replacing in the equation of state, the resulting expression is therefore simplified in term of specific volume:

P\cdot V = \frac{m}{M}\cdot R_{u}\cdot T

P\cdot \nu = \frac{R_{u}\cdot T}{M}

Since the neon is compressed isothermally, the following relation is constructed herein:

P_{1}\cdot \nu_{1} = P_{2}\cdot \nu_{2}

Where:

P_{1}, P_{2} - Initial and final pressure, measured in kilopascals.

\nu_{1}, \nu_{2} - Initial and final specific volume, measured in cubic meters per kilogram.

The change in specific volume is given by the following expression:

\frac{\nu_{2}}{\nu_{1}} = \frac{P_{1}}{P_{2}}

Given that P_{1} = 100\,kPa and P_{2} = 500\,kPa, the change in specific volume is:

\frac{\nu_{2}}{\nu_{1}} = \frac{100\,kPa}{500\,kPa}

\frac{\nu_{2}}{\nu_{1}} = \frac{1}{5}

The specific volume is reduced in 80 per cent due to isothermal compression.

Under the ideal gas supposition, specific enthalpy is only function of temperature, as neon experiments an isothermal process, temperature remains constant and, hence, there is no change in specific enthalpy.

Specific enthalpy remains constant.

8 0
3 years ago
I want a problems and there solutions of The inception of cavitation?​
Ugo [173]

Answer:

The overview of the given scenario is explained in explanation segment below.

Explanation:

  • The inception of cavitation, that further sets the restriction for high-pressure and high-free operation, has always been the matter of substantial experimental study over the last few generations.
  • Cavitation inception would be expected to vary on the segment where the local "PL" pressure mostly on segment keeps falling to that are below the "Pv" vapor pressure of the fluid and therefore could be anticipated from either the apportionment of the pressure.

    ⇒  A cavitation number is denoted by "σ" .

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Vapor lock occurs when the gasoline is cooled and forms a gel, preventing fuel flow and
Sergeu [11.5K]

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True

Explanation:

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Ayuda!<br> es para mañana
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No se ve la foto :( puedes a ser la pregunta otra ves?
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