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Murrr4er [49]
3 years ago
9

(12x6) - (3x2) how do you write in words to match the expression?

Mathematics
1 answer:
notka56 [123]3 years ago
7 0

twelve multiplied by six equals seventy two. Three multiplied by two equals six. Therefore seventy-two plus six equals seventy-eight
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Help subtract (xsquared +43x10)-(10xsquared-5x+10 express the answer in standard form
ad-work [718]

Answer:

\large\boxed{(x^2+43x+10)-(10x^2-5x+10)=-9x^2+48x}

Step-by-step explanation:

(x^2+43x+10)-(10x^2-5x+10)\\\\=x^2+43x+10-10x^2-(-5x)-10\\\\=x^2+43x+10-10x^2+5x-10\qquad\text{combine like terms}\\\\=(x^2-10x^2)+(43x+5x)+(10-10)\\\\=-9x^2+48x

6 0
4 years ago
Haven't run across one with three terms. help? preferably explain how you got the answer too!!​
const2013 [10]

Answer:

c^3 + c^2 - 7c + 20

Step-by-step explanation:

First, expand the expression using distributive property.

c^2(c+4) - 3c(c+4) + 5(c+4)

c^3 + 4c^2 - 3c^2 - 12c + 5c + 20

Lastly, simplify like terms.

c^3 + c^2 - 7c + 20

5 0
3 years ago
kim can mow the greens at the golf course twice as fast as shayla can. Working together, they can mow the greens in 4 hours. How
anyanavicka [17]

Answer: Kim can mow the greens alone in 6 hours.

Step-by-step explanation:

Let K be the rate Kim mows the greens, and S the rate for Shayla.  The rates K and S will be in greens/hour.

We know they can mow 1 green in 4 hours.  We can state this as a sum of their rates times the 4 hours equals one green:

(4 hours)*(K + S) = 1 green

We are told that K = 2S [Kim is twice as fast as Shayla]

Subsititute:

(4 hours)*(K + S) = 1 green

(4 hours)*(2S + S) = 1 green

4*(2S + S) = 1 green

12S = 1 green

Shalya's rate is 1 green/12 hours

Kim is twice as fast:  K = 2S

Kim's rate is 1 green/6 hours.

8 0
2 years ago
What number is equivalent to 6.75×10^-4
Leni [432]
Not sure what your asking but:
0.000675 is equivalent to 6.75x10^-4

hope this helps
4 0
3 years ago
(04.05 MC)
nika2105 [10]

Answer:

D

Step-by-step explanation:

Plug in and see.

Check A: Lets plug in (0,3) into y<2/3 x+2.

3<2/3 (0)+2

3<2 is not true so not A

Check C: Lets plug in (3,5) into y<2/3 x+2.

5<2/3 (3)+2

5<2+2

5<4 is not true so not C

Check B: Lets plug in (-3,1) into y<2/3 x+2.

1<2/3 (-3)+2

1<0 is not true so not B

Check D: Lets plug in (1,2) into y<2/3 x+2.

2<2/3 (1)+2

2<2/3+2 is true so D

6 0
3 years ago
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