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Inessa [10]
3 years ago
14

PLEWhat is the simplified form of V45? A. v5 B. 9.5 C. 3V5 D. 573

Mathematics
2 answers:
marysya [2.9K]3 years ago
7 0
It’s D I did the work
Dimas [21]3 years ago
4 0
V45
v9x5
v3^2x5
3V5
the answer is C
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From midnight to 6:00 am, the temperature rose 8°C. At 6:00 am, the temperature was − 20 ° -20°C. What was the temperature at mi
tekilochka [14]

Answer: -28 degrees Celsius

Step-by-step explanation:

-20 - 8 = -28

4 0
3 years ago
Wayne Gretsky scored a Poisson mean six number of points per game. sixty percent of these were goals and forty percent were assi
BartSMP [9]

Answer:

a) The mean for the total revenue he earns per game is of 13.2K while the standard deviation is of 3.63K.

b) 0.05 = 5% probability that he has four goals and two assists in one game

Step-by-step explanation:

In hockey, a point is counted for each goal or assist of the player.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval. The standard deviation is the square root of the mean.

(a) Find the mean and standard deviation for the total revenue he earns per game.

60% of six are goals, which means that 60% of the time he earned 3K.

40% of six are goals, which means that 40% of the time he earned 1K.

The mean is:

\mu = 6*0.6*3 + 6*0.4*1 = 13.2

The standard deviation is:

\sigma = \sqrt{\mu} = \sqrt{13.2} = 3.63

The mean for the total revenue he earns per game is of 13.2K while the standard deviation is of 3.63K.

(b) What is the probability that he has four goals and two assists in one game

Goals and assists are independent of each other, which means that we find the probability P(A) of scoring four goals, the probability P(B) of getting two assists, and multiply them.

Probability of four goals:

60% of 6 are goals, which means that:

\mu = 6*0.6 = 3.6

The probability of scoring four goals is:

P(A) = P(X = 4) = \frac{e^{-3.6}*(3.6)^{4}}{(4)!} = 0.19122

Probability of two assists:

40% of 2 are assists, which means that:

\mu = 6*0.4 = 2.4

The probability of getting two assists is:

P(B) = P(X = 2) = \frac{e^{-2.4}*(2.4)^{2}}{(2)!} = 0.26127

Probability of four goals and two assists:

P(A \cap B) = P(A)*P(B) = 0.19122*0.26127 = 0.05

0.05 = 5% probability that he has four goals and two assists in one game

5 0
2 years ago
The interest rate r required to increase your investment p to the amount a in t years is found by mc075-1.jpg. Find the interest
kotegsom [21]
I hope this is the answer :)
45.67=r

6 0
2 years ago
Read 2 more answers
Five friends buy tickets to a carnival. They each also spend $4 on a funnel cake. They spent a total of $60. How much does one t
Butoxors [25]

Answer:

$8 for each tickets

Step-by-step explanation: 60/5 equals 12

Each friends have $12

12-4=8

Each ticked cost 8 dollars.

4 0
2 years ago
Henry is saving money to buy a game. so far he has saved $12 , which is three-fourths of the total cost of the game. how much do
vazorg [7]
Henry has 3 / 4 0f total cost so,
Let ( a ) is total cost of game

So,
3/4 × a = total cost


12 = 3/ 4 × a

4 will multiply with 12 so,

12 x 4 = 3 a

48 = 3a

48 / 3= a

16 = a will be price of game


Mark as brainliest

5 0
3 years ago
Read 2 more answers
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