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serious [3.7K]
3 years ago
13

Two cars start to drive around a 2 km track at the same time. car x make one lap every 80 seconds while car y makes one lap ever

y 60 s
(a)how long will it take for the cars to be at their starting point again? give your answer in minutes.
(b)how long will it take to the faster car to be ahead by 15 laps? give your answer in hours.
Mathematics
1 answer:
Volgvan3 years ago
8 0

Answer:

20 minutes

Step-by-step explanation:

Both will meet again at start point after LCM(60,80) seconds.

That is 240 seconds.

in time slower car completes one lap, faster one covers 1 +20/80 lap, that is 1.25 laps. After 20 laps faster by slower car car will be 5 laps ahead, time =20*60 = 1200s = 20 minutes.

hope it help

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Veronika [31]

Answer:

\textbf{y = 9x + 21 }\\

Step-by-step explanation:

\textup{Given equation is: $4x + 36y = 80  $}\\\textup{This can be written in the form of $y = mx + a$ as follows}\\$ 36y = -4x + 80 $\\$ \implies y = \frac{80}{36} - \frac{4}{36}x $\\$ \implies y = \frac{-1}{9}x + \frac{20}{9} $\\\textup{This means that the slope of this line is $m = \frac{-1}{9}$}\\

\textup{Then the slope of the line perpendicular to this line would be \textbf{negative reciprocal of m}.}\\$i.e.,$ \textup{Slope of the perpendicular line would be $m_1 = \frac{-1}{\frac{-1}{9}}$}\\$\implies m_1 = 9$\\

\textup{The perpendicular line passes through the point $(3,6)$}\\\textup{Using the \textbf{point-slope formula}, we get:}\\

$$ y - y_1 = m(x - x_1) $$$ \implies y - 6 = 9(x - 3) $\\\textup{After solving this reduces to $y = 9x + 21$ }

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4 years ago
Write 0.600 in word form
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Six tenths. Hope that helps
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A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 450 gram setting. It
Arturiano [62]

Answer:

Test statistic = -2.25

P-value = 0.0199

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 450 gram

Sample mean, \bar{x} = 441 grams

Sample size, n = 16

Alpha, α = 0.05

Sample variance = 256

\sigma^2 = 256\\\sigma = \sqrt{256} = 16

First, we design the null and the alternate hypothesis

H_{0}: \mu = 450\text{ grams}\\H_A: \mu < 450\text{ grams}

We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{441 - 450}{\frac{16}{\sqrt{16}} } = -2.25

Now,

Degree of freedom =

=n-1 = 16-1=15

We can calculate the p-value from the table as:

P-value = 0.0199

Conclusion:

Since the p-value is smaller than the significance level we fail to accept the null hypothesis and reject it.

Thus, there is enough evidence to support the claim that the machine is under filling the bags .            

5 0
3 years ago
According to the line plot, what is the total distance run for all of the runners combined?
Ostrovityanka [42]

Answer:

Add all of them together. 1/5 + 2/4 + 4/3 + 3/2 = 53/15 miles

Step-by-step explanation:

1/5 + 2(1/4) + 4(1/3) + 3(1/2)

3 0
3 years ago
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