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ycow [4]
3 years ago
11

When Andrei surveyed 36 random seventh-grade students in the lunchroom, he found that 7 out of 9 would like to try or have

Mathematics
1 answer:
Alex73 [517]3 years ago
7 0

Answer:

About 630 seventh-grade students would like to snorkel

Step-by-step explanation:

if you do

7/9 x 90 equals 630/810 total students

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If a ball is thrown into the air with a velocity of 34 ft/s, its height (in feet) after t seconds is given by y = 34t − 16t2. Fi
Finger [1]

<u>ANSWER: </u>

If a ball is thrown into the air with a velocity of 34 feet per second, then velocity of the ball after 1 second is 2 feet per second

<u>SOLUTION: </u>

Given, a ball is thrown into the air with a velocity of 34 feet per second

Initial velocity (u) = 34 feet per second

And also given a relation between displacement and time = \mathrm{y}=34 \mathrm{t}-16 \mathrm{t}^{2} --- eqn 1

We need to find the velocity when t = 1 ; v = ?

We know that, v = u + at and \mathrm{s}=\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}

where v is instantaneous velocity and u is initial velocity

a is acceleration

t is time interval  

s is displacement

using the displacement and time relation eqn (1) we get

Now, when t = 1, displacement s = 34(1) – 16(1)

\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}=34-16

34 \times 1+\frac{1}{2} \times a \times 1^{2}=18

34+\frac{a}{2}=18

\begin{array}{l}{\frac{a}{2}=18-34} \\\\ {\frac{a}{2}=-16} \\ {a=-16 \times 2} \\ {a=-32}\end{array}

here, -ve sign indicates that object is in deceleration . so acceleration is -32 ft/s

now put a value in v = u + at

v = 34 + (-32)(1)

v = 34 – 32

v = 2 ft/s

Hence, velocity of the ball after 1 second is 2 ft/s

6 0
3 years ago
Point M is located in the third quadrant of the coordinate plane, as shown.
nevsk [136]

Answer:

It is in quadrant three

Step-by-step explanation:

The points of M means there x and y will both be negatives.

5 0
2 years ago
Read 2 more answers
The triangles below are congruent and their corresponding parts are marked.
Grace [21]

Answer:

The answer is below.

Step-by-step explanation:

8 0
3 years ago
Are 25 milligrams lighter or heavier than 25 centigrams
masya89 [10]

Answer:

<em>25 mg. is lighter than 25 cg.</em>

<em />

Step-by-step explanation:

<em>Well,</em>

<em />

<em>The prefix "milli" means thousandth and the prefix "centi" means hundredth.  So a milligram will be one-tenth of a centigram.</em>

<em />

<em>10 mg. = 1 cg.</em>

<em>25 mg. = 2.5 cg.</em>

<em />

<em>2.5 cg. < 25 cg.</em>

<em />

<em>25 mg. is lighter than 25 cg.</em>

8 0
2 years ago
Read 2 more answers
1. Select all values of x that are solutions to the equation: -2(x + 4)(3x - 18) = 0A) -6B) -4C) -2D) OE) 2F) 4G) 6
navik [9.2K]
\begin{gathered} -2(x+4)(3x-18)=0 \\ \text{There are two factors here which are} \\ -2(x+4)\text{ and} \\ (3x-18) \\ \text{This means, either} \\ 2(x+4)=0 \\ 2x+8=0 \\ 2x=-8 \\ \text{Divide both sides by 2} \\ x=-4 \\ OR \\ 3x-18=0 \\ 3x=18 \\ \text{Divide both sides by 3} \\ x=6 \\ \text{Therefore,} \\ x=-4\text{ or} \\ x=6 \end{gathered}

x = -4 OR x = 6

The correct options are B and G

6 0
1 year ago
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