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3 years ago

The diameter of a circular rug is 3 1/2 yards. what is the distance around the outside of the rug?

Mathematics

2 answers:

PolarNik [594]3 years ago

4 0

3.50× 2= distance
distance= 7??

xeze [42]3 years ago

4 0

The distance around the outside of the rug is equal to the perimeter of the rug (perimeter of circle)

Calculate the perimeter
p = π × d
p = 3.14 × 3 1/2
p = 3.14 × 3.5
p = 10.99

The distance is 10.99 yards

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Penny needs 30 cubic ft of sand to fill a sandbox. She plans to buy 10 bags of sand for her sandbox. Each bag contains 2.9 cubic

Romashka [77]

The correct answer is C.

Because: 2.9 multiplied by 10 bags equals 29cubic ft and she needs 30 cubic ft. So she would need to buy 11 bags to make sure she has enough sand for the whole thing. 11 x 2.9 = 31.9 which ensures she has enough for the whole thing including extra in case. So you answer would be Answer C.

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3 years ago

Please help me answer this. I think that for the first one the answer is A, but I am not sure. There are two parts to the questi

Anika [276]

Vector $PQ=(7-5, 3-4)=(2, -1)$ . $4RS=4 \cdot (4-8, 1-6) = 4 \cdot (-4, -5) = (-16, -20)$ . So the sum is $(-14, -21)$ .

For the second, the magnitude is the square root of the sum of the squares of the components. This is equal to $\sqrt{(-14)^2+(-21)^2} = \sqrt{637}=7\sqrt{13}$ .

4 0

3 years ago

Read 2 more answers

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Bogdan [553]

X=1/2 hope this helps <3

3 0

3 years ago

Read 2 more answers

Let f(x)=3x .

3241004551 [841]

You are multiplying the 3x by 6 which means c is correct

6 0

3 years ago

A woman bought some large frames for $18 each and some small frames for $8 each at a closeout sale. If she bought 21 frames fo

IrinaVladis [17]

Answer:

8 large frames and 13 small frames

Step-by-step explanation:

Given:
$18 each = large frames

$8 each = small frames

To Find:

⇒ Bought 21 frames for $248, find how many of each type she bought

Solve:

1 Large frame costs = 18 $

Therefore, x large frames costs = 18x $

{where x is the number of large frames she bought}

1 Small frame costs = 8 $

Therefore, x Small frames costs = 8y $

{where y is the number of small frames she bought}

By the given condition :

18x + 8y = 248 {equation 1}

x + y = 21 {equation 2}

Solve these equations simultaneously, from second equation we get :

x = 21- y

18⋅(21−y)+8y= 248

378 - 18y+8y = 248

-10y = -130

y = 13

Put y = 13 in eq x = 21- y

x = 21 - y

x = 21 - 13

x = 8

So the woman bought 8 large frames and 13 small frames.

~lenvy~

5 0

2 years ago