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Semmy [17]
3 years ago
9

Simplify:(y²+z²) -2yz​

Mathematics
1 answer:
VMariaS [17]3 years ago
5 0

Answer:

  (y-z)^{2}

Step-by-step explanation:

  (y^{2}+z^{2} ) -2yz\\\\y^{2} +z^{2} - 2yz\\\\y^{2} +2yz + z^{2}\\\\(y-z)^2\\

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If the vertex of a parabola is at (2, 3) and the point (0, -1) is also on the parabola, find an equation for the parabola. Write
STALIN [3.7K]

Answer:

y=-1(x-2)^2+3

Step-by-step explanation:

W have been given that the vertex of a parabola is at (2, 3) and the point (0, -1) is also on the parabola. We are asked to find the equation of parabola in the form y=(x-h)^2+k.  

We know that vertex form of parabola in form y=a(x-h)^2+k, where (h,k) in vertex of parabola.  

Upon substituting coordinates of vertex, we will get:

y=a(x-2)^2+3

To find the value of a, we will substitute coordinates of point (0, -1) as:

-1=a(0-2)^2+3

-1=a(4)+3

-1=4a+3

-1-3=4a+3-3

-4=4a

\frac{-4}{4}=\frac{4a}{4}

-1=a

Therefore, our required equation would be y=-1(x-2)^2+3.

3 0
3 years ago
If n ll m, find the value of x and the value of z.
aliina [53]
Answer: A

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7 0
3 years ago
Use a half-angle identity to find the exact value
Tatiana [17]

Given:

\cos 15^{\circ}

To find:

The exact value of cos 15°.

Solution:

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$\cos \frac{30^{\circ}}{2}=\sqrt{\frac{1+\cos \left(30^{\circ}\right)}{2}}

Using the trigonometric identity: \cos \left(30^{\circ}\right)=\frac{\sqrt{3}}{2}

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Let us first solve the fraction in the numerator.

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Using fraction rule: \frac{\frac{a}{b} }{c}=\frac{a}{b \cdot c}

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Apply radical rule: \sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}

           $=\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}

Using \sqrt{4} =2:

           $=\frac{\sqrt{2+\sqrt{3}}}{2}

$\cos 15^\circ=\frac{\sqrt{2+\sqrt{3}}}{2}

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3 years ago
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What is the answer to this
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