
Used:

Functions have the same derivatives if they differ a constant.
h(x) = f(x); g(x) = f(x) + const.
h'(x) = f'(x)
g'(x) = (f(x) + const.)' = f'(x) + (const.)' = f'(x) + 0 = f'(x)
h'(x) = g'(x)
Therefore yuor answer is A. f'(x)=g'(x)

Used:

The answer is c bc it is the correct answer
1/2x -5+2/3x =7/6x+4
First, you need to find the least <span>common </span>denominator between the 3 fractions....
2-3-6 The GCF is 6...
So to get rid of the fractions, multiply the whole equation by 2
6[ 1/2x -5+2/3x =7/6x +4 ]=
3x -30 +4x =7x +24
Now that we got rid of our fractions, we combine like terms...
3x -30 + 4x= 7x + 24
7x -30 = 7x + 24
-30 = 24 is not true
So, there is no solution
Hope this helps Nic
If you have seen this method in school before....
Maybe this will seem familiar
Good Luck!<span />
Answer:
7.07
Step-by-step explanation:
<h2><u>Length</u></h2>
a square has equal length on each side
hence is the perimeter is 20 it means that :
each side is 20/4 = 5
we can make a diagonal line which create 3 right angled triangles
2 sides of the triangle are 5 , this is the base and the height
to find the length we can make use of the Pythagoras theorem
c^2 = a^2 + b^2
c is the hypotenuse ( the diagonal;)
a and b are the opposite and adjacent
hence :
c^2 = 5 ^2 + 5^2
c^2 = 50
c = 
c = 7.071
to 3sf
<h3><u>diagonal length = 7.07</u></h3>
Answer:
A. 6^2/7 and (√6)^7
Step-by-step explanation:
Because we can't get 6 out of root as a whole we need to use the power to show its value when we do so.
The power of (√6)^7 has is seven and degree of the root is 2 so we have to put 2/7 over 6 when we take it out of root.