I'm going to assume you mean what units were used to translate the point. In that case: The x-coordinate was moved 2 units to the right and the y-coordinate was moved 7 units to the left.
Answer:
Bottom Right Graph (Absolute Value)
General Formulas and Concepts:
Step-by-step explanation:
When we apply the VLT to the 4 different graphs, we see that the only graph that actually passes the VLT is the absolute value graph. Therefore, that is our answer (none of the other graphs pass the VLT).
To find the maximum or minimum value of a function, we can find the derivative of the function, set it equal to 0, and solve for the critical points.
H'(t) = -32t + 64
Now find the critical numbers:
-32t + 64 = 0
-32t = -64
t = 2 seconds
Since H(t) has a negative leading coefficient, we know that it opens downward. This means that the critical point is a maximum value rather than a minimum. If we weren't sure, we could check by plugging in a value for t slightly less and slighter greater than t=2 into H'(t):
H'(1) = 32
H'(3) = -32
As you can see, the rate of change of the object's height goes from increasing to decreasing, meaning the critical point at t=2 is a maximum.
To find the height, plug t=2 into H(t):
H(2) = -16(2)^2 +64(2) + 30 = 94
The answer is 94 ft at 2 sec.
-5 + 7= 7 + (-5) they are the same just switched
