Answer
Find out the what fraction of the sandcastle did they build together .
To prove
Let us assume that the fraction of the sandcastle they build together be x .
As given
![Beatrice\ built\ about\ \frac{1}{3}\ of\ a\ sandcastle.](https://tex.z-dn.net/?f=Beatrice%5C%20built%5C%20about%5C%20%5Cfrac%7B1%7D%7B3%7D%5C%20of%5C%20a%5C%20sandcastle.)
![Linda\ built\ \frac{4}{7}\ of\ the\ same\ castle.](https://tex.z-dn.net/?f=Linda%5C%20built%5C%20%5Cfrac%7B4%7D%7B7%7D%5C%20of%5C%20the%5C%20same%5C%20castle.)
Than the equation becomes
![x = \frac{1}{3} +\frac{4}{7}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%2B%5Cfrac%7B4%7D%7B7%7D)
L.C .M of (3,7) = 21
solving
![x = \frac{7 + 3\times4}{21}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B7%20%2B%203%5Ctimes4%7D%7B21%7D)
![x = \frac{19}{21}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B19%7D%7B21%7D)
Therefore the fraction of the sandcastle did they build together be
![x = \frac{19}{21}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B19%7D%7B21%7D)
Hence proved
Since ΔABC ~ ΔEDC, ∠B = ∠D.
Since both triangles appear to be similar, the corresponding angles are the same, and corresponding sides are the same or have the same ratio.
We can write an equation to resemble the problem:
8x + 16 = 120
Solve for x.
8x + 16 = 120
~Subtract 16 to both sides
8x + 16 - 16 = 120 - 16
~Simplify
8x = 104
~Divide 8 to both sides
8x/8 = 104/8
~Simplify
x = 13
Therefore, the answer is 13.
Best of Luck!
Answer:
5 (5x1) , -10 -(5x2), 20(10x2), -40 -(20x2), 80(40x2)
so the next number should be previous number in the sequence multiplied by 2 and a negative sign.
-`(80x2) = -160
Answer:
42*7
Step-by-step explanation: