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klio [65]
3 years ago
12

Help me please i don't know what i'm doing please help

Mathematics
1 answer:
UNO [17]3 years ago
8 0

Answer: -1/9

Step by step explanation:

The common difference of an arithmetic sequence can be found by picking 2 consecutive terms, and subtracting the second from the first. For example, if I chose the terms 2 and 1 8/9, I would find the common difference by:

1 8/9 - 2, which is equal to -1/9.

You can confirm this by picking another pair of consecutive terms. Let's pick 1 7/9 and 1 2/3:

1 2/3 - 1 7/9 = -1/9, as 1 2/3 = 1 6/9, so 1 6/9 - 1 7/9 = -1/9

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Answer: your answer is 195

Step-by-step explanation:

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Find the sum of 2x 2 + 3x - 4, 8 - 3x, and -5x 2 + 2
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Shaun has five coins in his pocket. If he empties the coins onto a table, what is the probability that all five coins will land
Anastasy [175]

Answer:

A. 1/32

Step-by-step explanation:

Ok, the probability for one of the coins to land on heads is 1/2 cause a coin have to sides and chance is 50% that it will land on either of its sides.

If you have 2 coins the probability will be 1/2 for the first coin to land on heads and 1/2 for the second one. The overall probability for 2 coins would be (1/2)*(1/2)=1/4. You could also see it is 1/4 because all of the possible combinations of 2 coins are 4 (HH, HT, TH, TT) and HH is one of four.

It's the same if you have 5 coins. The probability will be (1/2)*(1/2)*(1/2)*(1/2)*(1/2)=1/32 in other words HHHHH is one of 32 possible combinations of 5 coins.

5 0
3 years ago
Consider the limit of rational function p(x)l q(x)
Helga [31]

#1

\\ \sf\bull\dashrightarrow {\displaystyle{\lim_{x\to c}}}\dfrac{p(x)}{q(x)}=\dfrac{0}{1}=0

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\\ \sf\bull\dashrightarrow {\displaystyle{\lim_{x\to c}}}\dfrac{p(x)}{q(x)}=\dfrac{1}{1}=1

  • Here limit tends to 1
  • Hence c=1

\\ \sf\bull\dashrightarrow {\displaystyle{\lim_{x\to 0}}}\dfrac{p(x)}{q(x)}=\dfrac{1}{0}=\infty

  • Here x tends to infty.
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For the fourth one limit also tends to zero

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2 years ago
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its 11 and 31

Step-by-step explanation:

got it right on test

7 0
3 years ago
Read 2 more answers
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